If you don't want the search to run right off the bat, you just need
to comment out or remove the line reading
searchControl.execute("lyponline");
Jeremy R. Geerdes
Effective website design & development
Des Moines, IA
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On Mar 11, 2009, at 4:14 PM, JimF wrote:
>
> I have a site search I created starting with the 'Hello World'
> example The only item left for me is not to have results appear until
> the 'search' button is selected. What changes in the code below do I
> need to make?
>
> Thanks.
>
> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://
> www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
> <html xmlns="http://www.w3.org/1999/xhtml";>
> <head>
> <title>My Google AJAX Search API Application</title>
> <script src="http://www.google.com/jsapi?key=mykey"; type="text/
> javascript"></script>
> <script language="Javascript" type="text/javascript">
> //<![CDATA[
>
> google.load("search", "1");
>
> function OnLoad() {
> // Create a search control
> var searchControl = new google.search.SearchControl();
>
>
>
> // Add in a full set of searchers
> var localSearch = new google.search.LocalSearch();
> var siteSearch = new google.search.WebSearch();
> siteSearch.setSiteRestriction("lyponline.com");
> searchControl.addSearcher(siteSearch);
>
> // Set the Local Search center point
> localSearch.setCenterPoint("New York, NY");
>
> // Tell the searcher to draw itself and tell it where to attach
> searchControl.draw(document.getElementById("searchcontrol"));
>
> // Execute an inital search
> searchControl.execute("lyponline");
> }
> google.setOnLoadCallback(OnLoad);
>
> //]]>
> </script>
> </head>
> <body>
> <div id="searchcontrol">Loading...</div>
> </body>
> </html>
>
> >
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