if you read the documentation, you will find that you can get pages as  
you have been, but submitting start values which are factors of 4  
(e.g., 0, 4, 8, 12, 16...).  You can also get up to eight results at a  
time by adding the rsz parameter and setting it to "large."  In this  
case, your start value needs to be a factor of 8 (e.g., 0, 8, 16, 24,  
32...).  Take a look at the standard url arguments, as well as the web- 
specific arguments at the link below:

http://code.google.com/apis/ajaxsearch/documentation/reference.html#_intro_fonje

Jeremy R. Geerdes
Effective website design & development
Des Moines, IA

For more information or a project quote:
http://jgeerdes.home.mchsi.com
http://jgeerdes.blogspot.com
http://jgeerdes.wordpress.com
[email protected]

Unless otherwise noted, any price quotes contained within this  
communication are given in US dollars.

If you're in the Des Moines, IA, area, check out Debra Heights  
Wesleyan Church!

And check out my blog, Adventures in Web Development, at 
http://jgeerdes.blogspot.com 
  !


On May 10, 2009, at 3:58 PM, Jagadeesh kasiram wrote:

>
> Hi,
>
>                This is the query i am using to retrive data, from  
> this query i am getting only four results.
>
> String text="http://ajax.googleapis.com/ajax/services/search/web?v=1.0&q= 
> "+URLEncoder.encode(searchString, "UTF-8");
>
>
> Now i am in a position to get more results.  i mean if i click next  
> button i need 5th to 8th result.for that i tried
>
> count=5;//value will change accordingly
>
> String text="http://ajax.googleapis.com/ajax/services/search/web?v=1.0&q= 
> "+URLEncoder.encode(searchString, "UTF-8") +"start="+ count;
>
>
> But for this query also i am getting only four results only.
>
> what shall i do to get next page result.
>
>
> Regards
> Jagadeesh
>
> >


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