I guess I'm not really understanding exactly what you're after, but I was able to get the second link with this line:
var link=google.feeds.getElementsByTagNameNS(entry.xmlNode,"http://www.w3.org/2005/Atom ","link")[1]; Additionally, I can obtain various properties like this: var href=link.attributes.href.nodeValue; If I'm not understanding what you're after, please don't hesitate to explain a little more. Jeremy R. Geerdes Effective website design & development Des Moines, IA For more information or a project quote: http://jgeerdes.home.mchsi.com http://jgeerdes.blogspot.com http://jgeerdes.wordpress.com [email protected] Unless otherwise noted, any price quotes contained within this communication are given in US dollars. If you're in the Des Moines, IA, area, check out Debra Heights Wesleyan Church! And check out my blog, Adventures in Web Development, at http://jgeerdes.blogspot.com ! On May 24, 2009, at 1:59 PM, Kevin wrote: > var tweets = function(){ > //alert("Tweet"); > //#cheney for testing :) > var feed = new google.feeds.Feed("http://search.twitter.com/ > search.atom?lang=en&q=+%23cheney"); > feed.setResultFormat(google.feeds.Feed.MIXED_FORMAT); > feed.load(function(result) { > if (!result.error) { > var container = document.getElementById("feed"); > for (var i = 0; i < result.feed.entries.length; i++) { > var entry = result.feed.entries[i]; > var content = entry.content; > var author = entry.author; > var authorLink = google.feeds.getElementsByTagNameNS(entry.xmlNode, > "author")[0]; > var authorUri = authorLink.firstChild.nodeValue; > // alert(authorUri); > > } > } > }); --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Google AJAX APIs" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/Google-AJAX-Search-API?hl=en -~----------~----~----~----~------~----~------~--~---
