Hi Saravanan, Wouldn't it be much easier to have each HREF link to your PHP script, pass the start variable and then call the Google API straight from PHP?
<A HREF="mypagingscript.php?start=32" TARGET="_SELF">Go to 32nd result and onwards</A> And then in your PHP script: is_numeric($_GET['start'])?$start=$_GET['start']:$start=0; $url = "http://ajax.googleapis.com/.../?v=1.0&q=";. $_SESSION['searchtext']."&start=".$start."..." $retray = json_decode(include($url)); That would save you a lot of mixing clientside, serverside, JS and so on... Good luck, Ruben (Blogborg) > v=1.0&q=" > > .$searchQuery."&start=".$pg->start."&rsz=large&key=ABQIAAAAPJbd6fVsvq3XRmiloFh50RToOL0JAC4cb7rJK5CdsUkjTh5NqBRYQKUCoDmCuE6fep07WNQcFQbjPQ&userip=203.193.157.39"; On Mar 29, 9:30 am, saravanan <[email protected]> wrote: > Hi, > > Now that i have setup everything, i am facing a problem of how to > traverse through the results page, by clicking on the links at the > bottom of the page. > > I am using the following code for the links to further search pages at > the bottom of this search page. > [code] > <a href="javascript: callSubmit('<? > echo $url = "http://ajax.googleapis.com/ajax/services/search/web? > v=1.0&q=" > > .$searchQuery."&start=".$pg->start."&rsz=large&key=ABQIAAAAPJbd6fVsvq3XRmiloFh50RToOL0JAC4cb7rJK5CdsUkjTh5NqBRYQKUCoDmCuE6fep07WNQcFQbjPQ&userip=203.193.157.39"; > > ?> '); " onclick="javascript: callSubmit('<? > echo $url = "http://ajax.googleapis.com/ajax/services/search/web? > v=1.0&q=" > > .$searchQuery."&start=".$pg->start."&rsz=large&key=ABQIAAAAPJbd6fVsvq3XRmiloFh50RToOL0JAC4cb7rJK5CdsUkjTh5NqBRYQKUCoDmCuE6fep07WNQcFQbjPQ&userip=203.193.157.39"; > > ?> '); target="_self"> > [/code] > In the callSubmit function in javascript, i have used as > > <script language="javascript" type="text/javascript"> > function callSubmit(newUrl) > { > document.getElementById("newQuery").value=newUrl; > alert(document.getElementById("newQuery").value); > document.searchForm.submit(); > } > </script> > > I am able to get the URL in the alert() window. But the form is not > submitted, and the javascript error reported is : Object does not > support this property or method. > > Please help me on this issue. > > regards, > > saravanan > > On Mar 25, 3:26 pm, Jeremy Geerdes <[email protected]> wrote: > > > The &start= is to be appended to thehttp://ajax.googleapis.comurlwhich you > > call from within your own application to get subsequent pages. The > > moreResultsUrl is simply to direct your users to where they can run a more > > comprehensive search on Google itself. I do not know what the parameters > > you asked about in that url are; you will never need to worry about them. > > > Jeremy R. Geerdes > > Effective website design & development > > Des Moines, IA > > > For more information or a project quote:http://jgeerdes.home.mchsi.com > > [email protected] > > > If you're in the Des Moines, IA, area, check out Debra Heights Wesleyan > > Church! > > > On Mar 25, 2010, at 1:45 AM,saravananwrote: > > > > Hi, > > > > Thank you very much for your reply. I have one another small query to > > > be clarified by you. > > > In the bottom of the page, we give the links as 1 2....n. > > > > You have suggested appending of the &start to the url of the query. > > > Shall i use the url as "http://www.google.co.in/search? > > > hl=en&rsz=large&q=i+need+an+apple&start=".$pg->start" or have i got to > > > use the initial url like "http://ajax.googleapis.com/ajax/services/ > > > search/web?v.....". > > > where the $pg-> start is getting the value of the start property from > > > the object $json->responseData->cursor->pages. > > > > Please suggest me. > > > > Further, google search url is like this "http://www.google.co.in/ > > > search?hl=en&rlz=1C1DVCC_enIN361IN361&q=i+need+an > > > +apple&start=20&sa=N". Can you tell me the meaning of the "rlz" and > > > &sa=N in the above URL. This for my knowledge only. > > > > Thank you.. > > > > On Mar 24, 9:29 pm, Jeremy Geerdes <[email protected]> wrote: > > >> Two things. First, add &rsz=large to your url. This will tell the API to > > >> return 8 results at a time instead of 4. And second, rather than looking > > >> at the $json->responseData->cursor->moreResultsUrl, check out the > > >> $json->responseData->cursor->pages array. This will contain an array of > > >> the pages you can get. Each element in the array will have a start > > >> property which you can use to build a new url for the RESTful API. > > >> Simply add &start=[one of these start properties] to get additional sets > > >> of results. Once you've exhausted all the pages you can get from the > > >> pages array, then you can direct users to the moreResultsUrl. > > > >> Hope that makes sense! > > > >> Jeremy R. Geerdes > > >> Effective website design & development > > >> Des Moines, IA > > > >> For more information or a project quote:http://jgeerdes.home.mchsi.com > > >> [email protected] > > > >> If you're in the Des Moines, IA, area, check out Debra Heights Wesleyan > > >> Church! > > > >> On Mar 24, 2010, at 2:35 AM,saravananwrote: > > > >>> Hi, > > > >>> I have currently used the following search query: i+need+an+apple. > > > >>> In my test site, i am using the JSON alongwith PHP to parse the search > > >>> results returned from Google and display them as per my need. > > > >>> The problem that i face currently is that I get only top 4 results and > > >>> get 8 page references in cursor object. I did get only one url for > > >>> more results in "moreResultsUrl" > > > >>> I want my page to be analogous to the google search page. I need more > > >>> results and also when i click on the next links in that page, it > > >>> should go to the next search result page. > > > >>> The code i am using is as follows, This code is in PHP. > > > >>> [code] > > >>> $ct = 0; > > >>> foreach( $json->responseData->results as $res) > > >>> { > > >>> ?> > > >>> <h4> <a href=" <? echo $res->url ?>" target ="_blank" > <? > > >>> echo ($res->title); ?> </a></h4> <? echo "<br />"; > > >>> echo $res->content."<br />"; > > >>> ?> <a href=" <? echo $res->url ?>" target ="_blank" > > >>> style="color:Green" > <? > > >>> echo ($res->url); ?> </a> <? echo "<br />"; > > >>> echo "Cached URL: ".$res->cacheUrl."<br />"; > > >>> } > > > >>> echo "<br /><br />"; > > > >>> foreach($json->responseData->cursor->pages as $pg) > > >>> { > > >>> ?> <a href=" <? echo $json->responseData->cursor->moreResultsUrl;?>" > > >>> target="_blank" > > > >>> <? echo $pg->label; > > >>> ?> </a> > > >>> <? > > >>> } > > >>> [/code] > > > >>> Anybody please help me in getting all links in the current page and > > >>> also tell me ways to get the link url to other search pages as like > > >>> those in google's page. > > > >>> Thanks, > > > >>>saravanan > > > >>> -- > > >>> You received this message because you are subscribed to the Google > > >>> Groups "Google AJAX APIs" group. > > >>> To post to this group, send email to > > >>> [email protected]. > > >>> To unsubscribe from this group, send email to > > >>> [email protected]. > > >>> For more options, visit this group > > >>> athttp://groups.google.com/group/google-ajax-search-api?hl=en. > > > > -- > > > You received this message because you are subscribed to the Google Groups > > > "Google AJAX APIs" group. > > > To post to this group, send email to > > > [email protected]. > > > To unsubscribe from this group, send email to > > > [email protected]. > > > For more options, visit this group > > > athttp://groups.google.com/group/google-ajax-search-api?hl=en. -- You received this message because you are subscribed to the Google Groups "Google AJAX APIs" group. 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