Rather than pasting code into the Group, could you provide a link to your page, working or not? Alternatively, if that is absolutely not possible, please pastebin the code and provide a link to that. Groups has a nasty habit of slaughtering formatting and such, which makes it exceedingly difficult to debug code pasted there.
Jeremy R. Geerdes Effective website design & development Des Moines, IA For more information or a project quote: http://jgeerdes.home.mchsi.com [email protected] If you're in the Des Moines, IA, area, check out Debra Heights Wesleyan Church! On May 12, 2010, at 1:23 PM, Marvin Serrano wrote: > Hello all, > > I was wondering if anyone could help me with this problem...I've been > trying to get the XML from a website, but for some reason, it stops > when I call feed.load and set up the function to do something with the > result. It's just test code; the code I have is below: > > var container = document.getElementById("feed"); > var feed = new google.feeds.Feed('https://www.babyage.com/rss/ > new_arrivals.xml'); > container.appendChild(document.createTextNode("ONE...")); > container.appendChild(document.createElement("br")); > //feed.setResultFormat(google.feeds.Feed.XML_FORMAT);//convert > to > XML format. > container.appendChild(document.createTextNode("TWO...")); > container.appendChild(document.createElement("br")); > feed.setNumEntries(20);//this ensures that 20 entries are always > loaded > container.appendChild(document.createTextNode("THREE...")); > container.appendChild(document.createElement("br")); > //by default, Google Feeds load only 4 entries. > container.appendChild(document.createTextNode("IT > WORKS!")); > container.appendChild(document.createElement("br")); > feed.load(the_result); > container.appendChild(document.createTextNode("FOUR...")); > container.appendChild(document.createElement("br")); > function the_result(result) > { > if(!result.error) > { > container.appendChild(document.createTextNode("IT WORKS!")); > } > else > { > container.appendChild(document.createTextNode("IT WORKS NOT!")); > } > } > container.appendChild(document.createElement("br")); > > It completely stops at the function declaration. If anyone can let me > know why this is happening, it would be greatly appreciated. > > Also, if it helps, here's my header... > > <!DOCTYPE html> > <html> > <head> > <title>Deal Arrivals</title> > <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.3/ > jquery.min.js"></script> > > <script type="text/javascript" src="http://www.google.com/jsapi? > key=ABQIAAAArpsj8meHaJehCEuTe7uNixTfNKF7wIarK7yIYTpwQygZOUjikRRQtI0ZlGf0BDfKz7wmTLr0gDNUTg"></ > script> > <script type ="text/javascript"> > google.load("feeds","1"); > > //the above code was in here. > > </script> > > </head> > </html> > > > Thank you in advance, > > Marvin Serrano > > -- > You received this message because you are subscribed to the Google Groups > "Google AJAX APIs" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/google-ajax-search-api?hl=en. > -- You received this message because you are subscribed to the Google Groups "Google AJAX APIs" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/google-ajax-search-api?hl=en.
