If your doing a feed search try this url

https://ajax.googleapis.com/ajax/services/feed/find?v=1.0&q=Official%20Google%20Blog

Is that the URL you found in the docs somewhere?

https://ajax.googleapis.com/ajax/services/feed/feed

If so can you post a link to it?


On Mar 17, 8:34 am, crazywizard <[email protected]> wrote:
> Am trying to use the python implementation for the feed-api but when I
> run the sample code, I get a 404 error. I have an api-key, so I don't
> understand what's wrong.
>
> Sample code:
>
> import urllib2
> import simplejson
>
> url = ('https://ajax.googleapis.com/ajax/services/feed/feed?'+
>        'v=1.0&q=Official%20Google%20Blog&key=ABQIAAAA3yxjuwRO-TvCe0atz-
> bXURSxacz9-9-
> HUriveZcWWM1mnHlsLBS0fBq1eNV8LD9XYfb23n6t83I8Tw&userip=192.168.0.1')
>
> request = urllib2.Request(url, None, {'Referer': 'http://www.nation.co.ke/'})
> response = urllib2.urlopen(request)
>
> # Process the JSON string.
> results = simplejson.load(response)
> # now have some fun with the results...
>
> Output:
>
> [root@localhost Desktop]# python feed.py
> Traceback (most recent call last):
>   File "feed.py", line 8, in <module>
>     response = urllib2.urlopen(request)
>   File "/usr/lib/python2.6/urllib2.py", line 124, in urlopen
>     return _opener.open(url, data, timeout)
>   File "/usr/lib/python2.6/urllib2.py", line 395, in open
>     response = meth(req, response)
>   File "/usr/lib/python2.6/urllib2.py", line 508, in http_response
>     'http', request, response, code, msg, hdrs)
>   File "/usr/lib/python2.6/urllib2.py", line 433, in error
>     return self._call_chain(*args)
>   File "/usr/lib/python2.6/urllib2.py", line 367, in _call_chain
>     result = func(*args)
>   File "/usr/lib/python2.6/urllib2.py", line 516, in
> http_error_default
>     raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
> urllib2.HTTPError: HTTP Error 404: Not Found
>
> P/S: Am a newbie, so keep it simple please.

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