Can i atleast approximate the sender's location by using gmail's mailserver
ip? is that possible.i am not looking for very accurate location.

On Fri, Apr 30, 2010 at 2:27 AM, Ikai L (Google) <[email protected]> wrote:

> From this page:
>
>
> http://compnetworking.about.com/od/workingwithipaddresses/qt/ipaddressemail.htm
>
>    - Google's *Gmail* service omits the sender IP address information from
>    all headers. Instead, only the IP address of Gmail's mailserver is shown in
>    Received: from. This means it is impossible to find a sender's true IP
>    address in a received Gmail.
>
>    - Microsoft's *Hotmail* service provides an extended header line called
>    "X-Originating-IP" that contains the sender's actual IP address.
>
>    - Emails from *Yahoo* (if untampered) contain the sender's IP address
>    in the last Received: entry
>
>
> On Thu, Apr 29, 2010 at 12:24 PM, sreenidhi b.s <[email protected]>wrote:
>
>> i used getheader() function on message and all i could gather is smtp id
>> but not the sender's ip address.please help me.here is the code sample.thank
>> you.
>> MimeMessage message=new MimeMessage(session,req.getInputStream());
>>
>> String mailSubject=message.getSubject();
>> Address[] sender=message.getFrom();
>> Address[] receiver=message.getAllRecipients();
>> Date date=message.getSentDate();
>> Header head = null;
>> /*Enumeration headers = message.getAllHeaderLines();
>>          String headerinfo="";
>>          while ( headers.hasMoreElements( ) ){
>>              head = (Header) headers.nextElement( );
>>              //out.println("<li>" + head.getName( ) + ": " +
>> head.getValue( )+ "</li>");
>>              headerinfo=" "+head.getName()+" "+head.getValue();
>>          }*/
>> String headerinfo=message.getHeader("Received"," ");
>> _log.log(Level.WARNING,headerinfo);
>>
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>
>
>
> --
> Ikai Lan
> Developer Relations, Google App Engine
> Twitter: http://twitter.com/ikai
> Delicious: http://delicious.com/ikailan
>
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