Thomas,

it is possible to pre-determine the solution list for given lower and upper
bounds x and y. But there can be enormous rows for a given (x,y) pair. And
there will be enormous rows containing (x,y) pairs. So I can not keep a
predetermined list.

Regards
Romesh

On Mon, May 3, 2010 at 5:52 AM, Thomas <[email protected]> wrote:

> I can't imagine what your data is. Is it possible to pre-solve the
> solution list z for every (x, y) pair and store them like (x, y, list
> of z). If it is the case, you can use a simple z=<somevalue> filter to
> get your single result.
>
> Thomas
>
> On 5月2日, 下午4時57分, romesh soni <[email protected]> wrote:
> > Tristan,
> >
> > sorry for the mistake. I wrote the wrong thing ( I realized this at night
> > when I went to bed for sleep)
> > It is field1<=1000<=field2. A given value will always be between the
> lower
> > and upper bound  (field1 and field2).
> >
> > Thanks
> > Romesh
> >
> > On Sun, May 2, 2010 at 11:20 AM, Tristan <[email protected]
> >wrote:
> >
> >
> >
> > > did you make an error or are you describing this condition?
> >
> > > 1000 <= field1 <= field2 <= 1000
> >
> > > On May 1, 10:26 am, romesh soni <[email protected]> wrote:
> > > > OK, let me explain the query which I need to run (I am putting the
> sql
> > > > server syntax for it, thats what I was working so far):
> > > > select *  from mytable where field1>=1000 and field2<=1000;
> >
> > > > Thats what I need to run on on datastore.
> >
> > > > Field1 and field 2 are have a relation. More specifically,  Field1
> > > <=field
> > > > 2. My db is such that when I search for any given integer say 1000,
> then
> > > the
> > > > db will return only one row for given condition : field1>=1000 and
> > > > field2<=1000;
> >
> > > > Regards,
> > > > Romesh..
> >
> > > > On Sat, May 1, 2010 at 4:42 PM, Tristan <[email protected]
> >
> > > wrote:
> > > > > Hey,
> >
> > > > > So, there's no more 1000 query limitation, that went away (unless
> it
> > > > > was put back in).
> >
> > > > > I see what you're saying though. Need to know more about what the
> > > > > problem is. I assume x and z are the two properties? It seems that
> x
> > > > > and z are correlated (since you guarantee that there is only one
> > > > > solution that meets the criteria). This correlation can probably be
> > > > > exploited to better solve the problem, but I need some constraints
> to
> > > > > work with. What is the relationship between x and z that guarantees
> > > > > you will have only one solution?
> >
> > > > > Tristan
> >
> > > > > On May 1, 2:30 am, romesh soni <[email protected]> wrote:
> > > > > > Hi Tristan,
> > > > > > The solution you provided is the best one among of those which I
> have
> > > > > found
> > > > > > so far. But this is not what I was looking for, my database is
> quite
> > > > > large
> > > > > > and its will grow continuously to millions of records in time.
> But
> > > there
> > > > > > will be only 1 matching record for my filter (x<=y and y>=z) If I
> try
> > > > > your
> > > > > > suggested approach,  then I will have to scan all records in
> > > loop.(1000
> > > > > > limitation)
> >
> > > > > > On Fri, Apr 30, 2010 at 6:58 PM, Romesh <[email protected]>
> > > wrote:
> > > > > > > I have been trying to find a workaround for this limitation and
> > > spent
> > > > > > > 2 days and read almost all blogs, discussion
> > > > > > > groups....................., but can not find a solution to it.
> Has
> > > > > > > any one able to find a way to handle this limitation? (The List
> > > > > > > property solution doesn't work.)
> >
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