Ahhh, I was calling r.put() outside the loop but that was throwing an error
so I moved it in. I had wondered about the difference between db.put() and
an r.put(), now I know! Still learning, thanks for the help.

On Fri, Sep 19, 2008 at 11:09 PM, Alexander Kojevnikov <
[EMAIL PROTECTED]> wrote:

>
> Iteration on the fetched list of model instances is not expensive.
> What IS expensive is calling put() 100 times.
>
> I suggest changing your code to this:
>
> results = Foo.all.filter...fetch(100)
> # Need to perform some operation on these 100 records
> for r in results:
>   r.column -=1
>
> # Save all models at once.
> db.put(results)
>
> # Now render results using template (will have to loop again).
> path = os.path.join(os.path.dirname(__file__), 'Foo.html')
>  template_values = {
>       'r': results,
>       }
> self.response.out.write(template.render(path, template_values))
>
> On Sep 20, 1:55 pm, Ethan <[EMAIL PROTECTED]> wrote:
> > I need to do something like this. It looks like in order to a) perform
> > some operation on my 100 records and update the datastore and b)
> > render the 100 records in a template, that I have to iterate through
> > the records twice.
> >
> > Is this the only way to do this if I want to use a template? Is there
> > a more efficient way?
> >
> > results = Foo.all.filter...fetch(100)
> >
> > # Need to perform some operation on these 100 records
> > for r in results:
> >    r.column -=1
> >    r.put()
> >
> > # Now render results using template (will have to loop again).
> > path = os.path.join(os.path.dirname(__file__), 'Foo.html')
> >
> >  template_values = {
> >        'r': results,
> >        }
> >
> > self.response.out.write(template.render(path, template_values))
> >
>

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