Hi djidjadji,

This will be less efficient than simply calling .count() on the collection
property, which doesn't require fetching the keys at all.

-Nick Johnson

On Tue, Jun 23, 2009 at 8:04 PM, djidjadji <[email protected]> wrote:

>
> You can construct a __key__ only query and count them up.
> Then you don't have to construct all the A objects just for counting.
>
> result = A.all(keys_only=True).filter('refprop =', b.key()).fetch(1000)
> numA = len(result)
>
> 2009/6/22 Nick Johnson (Google) <[email protected]>:
> > Hi johntray,
> >
> > On Sun, Jun 21, 2009 at 5:47 PM, johntray <[email protected]> wrote:
> >>
> >> Well yes I could add a count property to the B objects, but I'm really
> >> trying to understand more about how ReferenceProperty works.
> >
> > ReferenceProperty's collection attributes are just syntactic sugar for
> > creating and executing a query yourself. As such, all the same
> limitations
> > apply. In the case where you call len() on it, I believe this will result
> in
> > a count query being executed, which doesn't require Python to decode all
> the
> > entities, but does require the datastore to fetch all the index rows.
> > [snip]
>
> >
>


-- 
Nick Johnson, App Engine Developer Programs Engineer
Google Ireland Ltd. :: Registered in Dublin, Ireland, Registration Number:
368047

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