count > 1000 split according to time or any, example improvable with
dynamical increment (make dependant dayinc)
def get(self):#sums > 1000
import time
from datetime import datetime, timedelta
inc = datetime.now ()-timedelta(days = 1000)
dayinc = 10 #ok while return < 1000 every 10 days
sum = 0
while(inc < datetime.now()):
ads = Ad.all().filter("modified <", inc + timedelta(days =
dayinc)).filter("modified >", inc).count()
inc = inc + timedelta (days = dayinc)
sum=sum+ads
self.response.out.write(sum)
and sorting in pure python with one's own order always works or use
the pattern called "comparable",
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