Ok. Is there an alternative solution? I use the same login to sign-in to iGoogle/Gmail/etc. as I do to sign- in to my GAE application. In fact, when I "sign-out" of the GAE application, I am also signed-out of iGoogle and my Gmail altogether.
I'm using the "url" module mode in my gadget. And, it actually works pretty well. I just have to sign-in. Although, a couple versions of IE don't actually allow the sign-in. So, that is another reason I am looking into some sort of auto-sign-in, or a proxy sign-in of some sort... On Mar 24, 2:23 pm, "Ikai L (Google)" <[email protected]> wrote: > No, this will not happen. A gadget is just a JavaScript widget. > gadgets.io.makeRequest will not pass a usable User ID or session > information. > > > > > > On Wed, Mar 24, 2010 at 8:13 AM, redsox2005 <[email protected]> wrote: > > I have been looking at the gadget documentation, and I do not see how > > I can have a gadget automatically login to my App Engine application. > > > Has anyone done this yet? I assume so - but I am a bit unsure how to > > proceed. I had hoped that just by being logged-in , and viewing your > > iGoogle page, that the login to App Engine would simply occur > > automatically. > > > But, I am wrong about the "auto-login".... > > > -- > > You received this message because you are subscribed to the Google Groups > > "Google App Engine" group. > > To post to this group, send email to [email protected]. > > To unsubscribe from this group, send email to > > [email protected]. > > For more options, visit this group > > athttp://groups.google.com/group/google-appengine?hl=en. > > -- > Ikai Lan > Developer Programs Engineer, Google App > Enginehttp://googleappengine.blogspot.com|http://twitter.com/app_engine -- You received this message because you are subscribed to the Google Groups "Google App Engine" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/google-appengine?hl=en.
