Thanks agian. A lite side questions. Any pointers how to do it the other way around? That is instead of storing a ReferanceProperty on Label, storing the Lable keys in a ListProperty on Item. Can't figure out how to do it in just 2 quires.
..fredrik On 8 jun 2010, at 14.22, djidjadji wrote: > If your Item object only has a name property you can put this name in > place of the ReferenceProperty. > Or give the Item a key_name that is equal to the name. Then you can > get the name with > > Label.item.get_value_for_datastore(label).name() > > This saves you the fetching of the Item objects. > > 2010/6/8 Fredrik Bonander <[email protected]>: >> 2. The page renders really fast, but usage is about 2345cpu_ms >> 2112api_cpu_ms when I knock it up to 30 items and 120 labels. Is any thing >> else one could do? I could use memcache but this will be used at a page >> where it's displayed only after an update. > > -- > You received this message because you are subscribed to the Google Groups > "Google App Engine" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/google-appengine?hl=en. > -- Fredrik Bonander [email protected] +46 70 943 5441 - the infinite power of the creative mind - -- You received this message because you are subscribed to the Google Groups "Google App Engine" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/google-appengine?hl=en.
