Don't model it like this :).
Seriously, do something like this:
class FriendShip(db.Model):
account_id = db.IntegerProperty() # Sure use refprop if you want,
waste of space IMHO
Then create it like this:
friendship = FiendShip(parent=db.Key.from_path('User', USER_1_ID, 'Friend',
USER_2_ID), account_id=USER_2_ID)
# Then make another one under the other guy:
friendship_sym = FiendShip(parent=db.Key.from_path('User', USER_2_ID,
'Friend', USER_1_ID), account_id=USER_1_ID)
db.put([friendship, friendship_sym])
That does this do?
* Testing for friendship: db.get(db.Key.from_path('User', USER_1_ID,
'Friend', USER_2_ID)) -- if not None they are friends.
* Friends of user one? FriendShip.all(ancestor=db.Key.from_path('User',
USER_1_ID)) # Note--this is always consistent! Woohoo!
* Everyone that is friends with user 2?
FriendShip.all().filter('account_id', USER_2_ID) # Not always consistent,
but pretty close :)
-Jesse
On Tuesday, November 20, 2012 12:45:34 PM UTC-6, Emmanuel Mayssat wrote:
>
> I have a model as follow
>
> class User(db.Model):
> name = db.StringProperty(required=True)
>
> class Friendship(db.Model):
> user1 = db.ReferenceProperty(required=True,
> collection_name="user1_set")
> user2 = db.ReferenceProperty(required=True,
> collection_name="user2_set")
>
> I can create users and friendship relationship between them.
> Now the question is:
> How can I find if to people are already friends?
>
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