Thank you Daniel, it works!
Il giorno lunedì 1 maggio 2017 17:41:15 UTC+2, Giuseppe Ricci ha scritto:
>
> Hi,
>
> I'm new with Google Chart. I'm retrieving with PHP weather data from
> OpenWeather API.
> I pass to javascript the 2 data arrays with dates and temperatures to
> build a data array used to the google chart.
> My code is:
>
> <script type="text/javascript">
> var temp=new Array();
> <?php
> for($i=0;$i<count($temperature);$i++){?>
> temp[<?php echo $i; ?>]="<?php echo "$temperature[$i]"; ?>";
> <?php
> }?>
>
> var dataora=new Array();
> <?php
> for($i=0;$i<count($dataora);$i++){
> ?>
> dataora[<?php echo $i; ?>]="<?php echo "$dataora[$i]"; ?>";
> <?php
> }?>
>
> google.charts.load('current', {'packages':['line']});
> google.charts.setOnLoadCallback(drawChart);
>
> function drawChart() {
> var data2 = new Array();
>
> data2[0] = [ 'Date', 'Temperature' ];
> for (i = 0; i < temp.length; i++) {
> data2[i + 1] = [ dataora[i], parseFloat(temp[i]) ];
> }
> var data = google.visualization.arrayToDataTable(data2,
> false);
>
> document.write(JSON.stringify(data));
>
> var options = {
> chart: {
> title: 'Previsioni Temperatura',
> subtitle: 'in °C'
> },
> width: 1000,
> height: 500,
>
> }
> };
>
> var chart = new
> google.charts.Line(document.getElementById('chart_div'));
> chart.draw(data, google.charts.Line.convertOptions(options));
> }
>
> </script>
>
> <div id="chart_div" style="50%"></div>
>
> Opening the console I see this error:
>
> Uncaught Error: Container is not defined
>
> Can someone help me to solve this error?
> Thanks.
>
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