Http://www.spoj.pl/problems/CLEAR

On 22 Jul 2009, at 01:26, khanh le <[email protected]> wrote:

>
> Dear people,
> i have a exercise, so i want to you solve it. you must code by C++  
> langguage
> now, read the exercise below:
>
> Peter has just found a definition of clear numbers as the following:  
> for each positive integer n, we form another number by summing the  
> squares of the digits of n. We repeat this procedure. If at some  
> step, we obtain the number 1 then n is called a clear number. For  
> example, for n=19, we have:
>
> 19 → 82 (= 12 +92) → 68 → 100 → 1
>
> Thus, 19 is a clear number.
>
> Not all numbers are clear numbers. For example, for n=12, we have:
>
> 12 → 5 → 25 → 29 → 85 → 89 → 145 → 42 → 20 → 4 →  
> 16 → 37 → 58 → 89 → 145
>
> Peter is very interested in this definition of clear numbers. He  
> issued a challenge to the landlord: given a positive integer n, find  
> S(n), the clear number succeeding n, i.e. S(n) is the minimum clear  
> number greater than n. However, this question is so easy for the  
> landlord that he challenged Peter with another problem: given two  
> positive integers n and m (1 ≤ n, m ≤ 1015), find the number  
> Sm(n)=S(S(…S(n) )) which is the mth clear number succeeding n.
>
> Please help Peter to solve the task!
>
> Input
>
> The first line contains t (0 < t ≤ 20) , the number of test cases.
>
> Each line in the next t lines contains two positive integers n and m.
>
> Output
>
> Print t lines, each line contains the result of the corresponding  
> test case.
>
> Example
>
> Input
> 2
> 18 1
> 1 145674807   
>
> Output
> 19
> 1000000000
> Notes
>
> There are 50% of the test cases in which 1 ≤ n, m ≤ 107.
>
>
> -- 
> Regard!
> Khanh
>
> >

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