Yes, you can, it's a native 64-bit integer. On Wed, Sep 2, 2009 at 7:36 PM, MagicLi <[email protected]> wrote:
> > Oh, it is great! "__int64" I use visual studio C++ 2008. Can I use > __int64 as normal int type, like "+ - * /" these operators? > > On Sep 2, 1:00 pm, jalves <[email protected]> wrote: > > Hi, > > > > It depends on your compiler but all should have 64 bit integers: > > - GNU C++ type: long long > > - VC++ type: __int64 > > > > If you simply want to reach 2^32-1 and don't need negative numbers > > you may simply use the data type "unsigned long" which goes from 0 to > > 2^32-1. > > > > I hope it helps. > > > > João Alves > > > > On Sep 2, 4:36 pm, MagicLi <[email protected]> wrote: > > > > > > > > > C++ in Windows, both int and long type are 4bytes, that means the > > > biggest number can store is 2^31-1=2,147,483,647 , you may say the > > > unsigned int could be larger, yes, but only twice lager, still under > > > 10^10; for question like Round 1 B, B. Number Sets, the large input : > > > 1 <= A <= B <= 10^12, 10^12 cannot be stored in C++'s built-in type. > > > So how to do that? > > > > -- João Alves --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "google-codejam" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/google-code?hl=en -~----------~----~----~----~------~----~------~--~---
