This is part of my code:

@res    = $dstr =~ /$str/gm;
print 'Case #'.($cnt+1).': '....@res."\n";

$dstr is comma separated list of words, $str is my computed
expression. @res is the results array, when evaluated as scalar (as in
second line), it will give number of elements (matches). That's all.


On Sep 4, 5:36 pm, Dhruva Sagar <[email protected]> wrote:
> No my friend, maybe you have the wrong idea, RegExp won'g help you count,
> but only test, here is my code in Ruby :
> It should be pretty easy to understand.
>
> N.times do |i|
>   r = Regexp.new(input[i+D+1].gsub('(','[').gsub(')',']').to_s)
>   count = 0
>   words.each do |w|
>     count+=1 if !r.match(w).nil?
>   end
>   output.puts "Case ##{i}: #{count}\n"
> end
>
> Thanks & Regards,
> Dhruva Sagar.
>
> Ogden Nash <http://www.brainyquote.com/quotes/authors/o/ogden_nash.html>  -
> "The trouble with a kitten is that when it grows up, it's always a cat."
>
> On Fri, Sep 4, 2009 at 8:40 PM, Satyajit Malugu
> <[email protected]>wrote:
>
>
>
> > You guys are all damn good at regex's I think. For the life of me, I simply
> > thought regex's can't be done because I have to count the number of
> > matches.
> > Can you give the regex you've used?
>
> > On Fri, Sep 4, 2009 at 5:21 AM, krzych <[email protected]> wrote:
>
> >> Hi,
>
> >> I solved first problem correctly in Perl for both small and large data
> >> sets. I just used regular expression and I think that this was the
> >> easiest (and requiring only a few lines of code) way to solve this
> >> task. Since I'm not familiar with Perl I had some problems and my
> >> regular expression is overcomplicated, but since it was working, I
> >> left it like it was.
>
> >> Cheers,
> >> Krzysztof.
>
> >> On Sep 4, 10:50 am, KeJo <[email protected]> wrote:
> >> > Hi,
>
> >> > anyone solved all problems correctly using perl?
>
> >> > I did it, but I feel there could be better ways to do it in perl.
> >> > Please let me know so that I can compare.
>
> >> > Regards,
> >> > KeJo
>
> > --
> > Satyajit
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