IO manipulators are your friends (include iomanip):
cout << "Case #" << i+1 << ": " << setfill('0') << setw(4) << res <<
endl;
On Sep 5, 8:24 am, MagicLi <[email protected]> wrote:
> Like in qualification round for Problem C, we have to show 0000
> instead of 0, I did it in a ugly way, change int to string type and
> then add '0' if num<1000, add '00' if num<100, add '000' if num<10;
> can anyone have a better way? BTW, do not use C-style output like
> fprintf(ofp, "Case #%d: %04d\n", t, d[i-1][18]); because I prefer
> ofstream instead of C-style FILE*.
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