In the contest analysis of the problem, it is written
r' (2, 1) + c' (1, 2) = (r, c) - (1, 1).
Solving, we get r+c = 2 mod 3, and
r' = r - 1 - (r+c-2)/3, and c' = c - 1 - (r+c-2)/3.
Can anyone explain the above thing?
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups
"google-codejam" group.
To post to this group, send email to [email protected]
To unsubscribe from this group, send email to
[email protected]
For more options, visit this group at
http://groups.google.com/group/google-code?hl=en
-~----------~----~----~----~------~----~------~--~---
