@Antoine: can u tell me ur user name on codejam. I would like to see your
code.
Regards,
Mahendra Kariya
http://www.mahendrakariya.blogspot.com


On Sat, Sep 12, 2009 at 3:00 PM, Nzeyimana Antoine <[email protected]>wrote:

>
> You are right, you have to stop the loop at value when you already
> have that one in chain(in order to avoid useless repetitons) or just
> stop at a value equal to one(note that 1 has the same value in all
> bases: 2 ... 9) . Then you have to check if a given
> number(increamentally from 2 to max_int) has a happy chains in three
> bases provided . This solved my large input in around 2.5 minutes
> using Java on a 2.2GHz dual CPU, core2duo laptop, but I hope it should
> be much less with other languages like C .
> This problem was relatively easy for me to understand and solve
> because I did a similar one in TopCoder(@least building chain of
> digits square sum in base 10 ), but I didn't undertand the logic of 1C
>  ; so my question is ' Is there any big influence from previous
> exercises/contests or experiences to solve quickly these problems ?'.
>
> On 9/12/09, MntlChaos <[email protected]> wrote:
> >
> > Why would you do that? It's happy if it ever reaches 1. If it gets
> > into a different loop, it's unhappy. However, you are correct that 8
> > is not happy in base 10: 8 => 64 => 52 => 29 => 85 => 89 => 145 => 42
> > => 20 => 4 => 16 => 37 => 58 => 89, at which point we have a cycle (89
> > appeared twice).
> >
> > But 7 IS happy in base 10: 7 => 49 => 97 => 130 => 10 => 1
> >
> > On Sep 12, 1:18 am, Mahendra Kariya <[email protected]> wrote:
> >> I guess in the first ques of Round 1A, we have to check only until the
> sum
> >> of squares of digits is not a single digit integer. Say, for sum number,
> >> if
> >> we get the sum of square of digits 8, we stop there and declare it to be
> >> unhappy without doing 8*8 = 64 .
> >>
> >> Regards,
> >> Mahendra Kariyahttp://www.mahendrakariya.blogspot.com
> > >
> >
>
> --
> Sent from my mobile device
>
> >
>

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