The algorithm is right anyway.
Have you tried to run the test case with length of 61 and maximum number 
of unique characters ?
@Luke: I see that you're using `whitespace` language for problem A. It's 
amazing that you still use 6 different languages to solve all the 
problems. :)

Ketan Joshi wrote:
> I used Perl. How do I find out how an integer is represented? (32bit 
> vs 64bit)?
>
> Is the logic ok?
>
> ~KeJo
>
> On Sun, Sep 13, 2009 at 5:24 PM, Luke Pebody <[email protected] 
> <mailto:[email protected]>> wrote:
>
>
>     Maybe you were using a 32-bit integer?
>
>     On Sun, Sep 13, 2009 at 12:51 PM, Ketan Joshi
>     <[email protected] <mailto:[email protected]>> wrote:
>     > FYI, I have handled the special case where there is only one
>     unique char in
>     > the number. In that case I assign '1' to that char and return
>     base as 2 as
>     > there can not be unary numbers
>     > ~KeJo
>     >
>     > On Sun, Sep 13, 2009 at 5:20 PM, Ketan Joshi
>     <[email protected] <mailto:[email protected]>>
>     > wrote:
>     >>
>     >> Hi,
>     >> I used the below logic to solve this:
>     >> 1) find number of unique chars in the input number. This
>     becomes the base
>     >> in which it will have lowest value.
>     >> 2) assign '1' to first char
>     >> 3) assign '0' to second unique char that appears in the input num
>     >> 4) assign 2..base-1 to each unique char that appears in the
>     input in the
>     >> increasing order
>     >> -- So cats becomes 1023 and zig becomes 102
>     >> 5) result = 0;
>     >> for (i=0;i++;i<length of num){
>     >>   result = result * base + number representing char[i]
>     >> }
>     >> output result.
>     >> This logic worked fine for small input. But I got "incorrect"
>     response for
>     >> large input.
>     >> Can someone tell me if this logic is flawed in any sense?
>     >> Regards,
>     >> KeJo
>     >> --
>     >> Blog: http://beingkejo.wordpress.com
>     >
>     >
>     >
>     > --
>     > Blog: http://beingkejo.wordpress.com
>     >
>     > >
>     >
>
>
>
>
>
> -- 
> Blog: http://beingkejo.wordpress.com
>
> >


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