64 bit longs  start to overflow about 10**18.  Java has a BigInteger infinite 
precision integer class that I've use in a couple of these problems when 
computations start approaching that size.  The C++ code I've looked at used 
long long variables which I think are 128 bits.  They are still going to 
overflow eventually, but apparently they are big enough to solve all code jam 
problems.

For some problems, like Next Number in this round, you can just treat the 
number as a string an manipulate an array of digits.  There is no need to 
turn it into a binary representation.

Best regards,
-Ken

On Sunday 13 September 2009 22:17:10 Carlos Guia wrote:
> Most likely overflow, 32bit integers will overflow in the large set.
> Carlos Guía
>
> On Sun, Sep 13, 2009 at 11:56 PM, Seedrick <[email protected]>wrote:
> > hi!!
> >
> > i used the exaclty same logic....
> > and got the small input correct but the large one wrong...
> >
> > What could be the problem with this logic? I have tried all sorts of
> > possible cases but could not figure this out.
> >
> > On Sep 13, 4:50 pm, Ketan Joshi <[email protected]> wrote:
> > > Hi,
> > > I used the below logic to solve this:
> > >
> > > 1) find number of unique chars in the input number. This becomes the
> > > base
> >
> > in
> >
> > > which it will have lowest value.
> > > 2) assign '1' to first char
> > > 3) assign '0' to second unique char that appears in the input num
> > > 4) assign 2..base-1 to each unique char that appears in the input in
> > > the increasing order
> > > -- So cats becomes 1023 and zig becomes 102
> > > 5) result = 0;
> > > for (i=0;i++;i<length of num){
> > >   result = result * base + number representing char[i]}
> > >
> > > output result.
> > >
> > > This logic worked fine for small input. But I got "incorrect" response
> >
> > for
> >
> > > large input.
> > > Can someone tell me if this logic is flawed in any sense?
> > >
> > > Regards,
> > > KeJo
> > >
> > > --
> > > Blog:http://beingkejo.wordpress.com
>
> 




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