For the third test case you have originally: (2, 1, 1, 0)
You do the following swaps:
(2, 1, 0, 1)
(1, 2, 0, 1)
(1, 0, 2, 1)
(0, 1, 2, 1)

On Sat, Sep 26, 2009 at 8:45 PM, Ken Corbin <[email protected]> wrote:

>
> So much for my dreams of honor and glory.  Looks like in the bottom third
> of
> contestants who are going to score a big fat zero.  Spent too much time
> working out a perfectly good solution to problem A that didn't solve even
> the
> sample input.  How in the world can the solve the last test case in 4
>  swaps
> instead of 5?  And was still working on problem B when time ran out.
>
> It was a well run contest, and I in special awe of the twisted minds that
> make
> up these problems.  Will probably be back next year, but right now I'm
> going
> to spend the rest of my weekend trying to solve these things.
>
> Thanks Google
> -Ken
>
>
>
> >
>


-- 
Asmaa Magdi (Also known as ACMaa :P)

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