i have written i<A.size().....not i<=A.size()....
i think thats not error..and i have tried it also

On May 28, 5:35 pm, Bharath Raghavendran <[email protected]> wrote:
>  I dont know what the question is or what the algo is supposd to do. But i
> guess the error is happening at this point :
> A.at(A.size())
>
> maybe you need to do A.at(A.size()-1) ?
>
> On 28 May 2010 17:49, Aamir Khan <[email protected]> wrote:
>
> > I was doing some practice for codeforces round 15 to be held in around
> > 27 hours from now....
> > I have written the C++ source code for codeforces round 14/A problem
> > (Letter)...
> > I am getting runtime error which i am not able to understand...
> > Please help..
>
> > Error:
>
> > terminate called after throwing an instance of 'std::out_of_range'
> >  what():  vector::_M_range_check
> > Aborted
>
> > Source Code:
> > /**************
> > Header Files
> > **************/
>
> > #include <iostream>
> > #include <vector>
> > #include <cstdio>
> > #include <cstdlib>
> > #include <stdexcept>
> > #include <string>
> > #include <iomanip>
>
> > using namespace std;
>
> > typedef vector<int> vi;
>
> > int main()
> > {
> > int row,col;
> > cin>>row>>col;
> > const int cols=col;
> > const int rows=row;
> > char Array[rows][cols];
> > string sentence;
> > vi  A;
> > vi  B;
>
> > for(int  i=0;i<rows;i++)
> > {  cin>>sentence;
> >  for (int j=0;j<cols;j++)
> >   {    Array[i][j]=sentence[j];
> >            if (Array[i][j]=='*')
> >        {  A.push_back(i);
> >               B.push_back(j);  }
>
> >   }
> > }
>
> > for(int i=A.at(0);i<A.at(A.size());i++)
> > {
> >  int max_B=0;
> >  int min_B=row-1;
> >  for ( unsigned l=0;l<B.size();l++)
> >        {
> >                if(max_B < B.at(l))
> >                max_B=B.at(l);
> >                if(min_B > B.at(l))
> >                min_B=B.at(l);
> >        }
>
> >  for (int j=min_B;j<max_B;j++)
> >   {   cout<<Array[i][j];
> >   }
> > }
>
> > cin.get();
> > cin.ignore();
> > return 0;
> > }
>
> > And if you have better algorithm to solve the problem then please
> > share it here....
>
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