I was reading about Graphs. Almost all texts, are solving problems with
acyclic graphs only. So I just wanted to try cyclic graph.

Carlos,

As you said, its really difficult to come up with a generic solution it
seems... But still me and my friend Shyam is working on this. We are just
discussing all the possibilities like 'using a counter in the node and
incrementing it till it reaches the degree of that node, book keeping of
visited nodes from current node...' We are still working on this... *:)*

On Mon, Nov 22, 2010 at 10:57 PM, Carlos Guia <[email protected]> wrote:

> reach the other. So, if I mark node 1 as visited at first, the program will
>> start from 1 and lets say it touches 2 and then it ll touch 3. From 3, it
>> has to go to 1 and by that time node 1 is marked as visited. So program 'll
>> halt there and 'll give wrong result.
>
> This part, for that example, can easily be solved as this
>
> for each node n,
>   mark all nodes as not visited
>   start walk from n
> end for
>
> However, I don't hit that solves the problem you want, I'm pretty sure
> there are other graphs that actually need to visit a node more than once. I
> haven't put much thought to it, but the problem the strikes me as NP-hard.
> If I'm correct, then you shouldn't be able to solve it efficiently for the
> general case. For a small number of nodes you could backtrack or use dynamic
> programming.
>
> Where does this problem come? Is it a contest problem, you created it out
> of curiosity, school assignment, etc?
>
> Carlos Guía
>
>
> On Mon, Nov 22, 2010 at 4:37 AM, Sakthi Priyan <
> [email protected]> wrote:
>
>> I am sorry. I didn't explain my problem clearly at first shot.
>>
>> It goes like this
>>
>> Assume there are five nodes in a graph. I am giving the Adjacency Matrix
>> here.
>>
>>   1 2 3 4 5
>> 1 0 1 1 1 1
>> 2 1 0 1 0 0
>> 3 1 1 0 0 0
>> 4 1 0 0 0 1
>> 5 1 0 0 1 0
>>
>> Now I need to visit all the nodes with minimum weights crossed. This is
>> the problem :(
>>
>> Here we have two closely connected components (CCC), 123 and 145. And node
>> 1 acts like a bridge between those CCC. If I enter any of those CCC, I need
>> to touch node 1 again to reach the other. So, if I mark node 1 as visited at
>> first, the program will start from 1 and lets say it touches 2 and then it
>> ll touch 3. From 3, it has to go to 1 and by that time node 1 is marked as
>> visited. So program 'll halt there and 'll give wrong result.
>>
>> Please suggest...
>>
>>
>> On Mon, Nov 22, 2010 at 9:52 AM, vineel yalamarth <
>> [email protected]> wrote:
>>
>>>
>>>
>>> Try using a visited flag for all the  nodes. Initialise it to zero and
>>> toggle it when you traverse through it,.Based on status of visited flag, you
>>> can avoid visiting the visited nodes.
>>>
>>> Regards,
>>> Vineel.
>>>
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>>
>>
>>
>> --
>> - Thanks and Regards,
>>
>> *Sakthipriyan*
>>
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-- 
- Thanks and Regards,

*Sakthipriyan*

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