I have put a sample first effort of coding this at http://ideone.com/Uu7ru .

The central idea is that in order for a set of k elements to be pure
for n, the initial sequence up to and including k must be pure for k.
Therefore, if we know how many sets of any given size are pure for k,
we can work out how many sets of k elements are pure for n.

The programme here is extremely inefficient: it calculates the value
of f(3,2) many many times. However, it is fast enough for the small
case: http://ideone.com/acRHe.

However, the large case needs something smarter: http://ideone.com/UyEnJ

More to follow...

On Sat, Apr 9, 2011 at 11:01 AM, Luke Pebody <[email protected]> wrote:
> Let us try and work out what the pure sets for 2-6 are:
>
> 2. In order for a subset of {2} to be pure for 2, 2 must be in the set. Thus
> the only pure set is {2}. This is pure for 2 because the index of 2 is 1.
>
> 3. In order for a subset of {2,3} to be pure for 3, 3 must be in the set.
> The only possibilities are {3} and {2,3}. {3} is pure for 3 because the
> index of 3 is 1. {2,3} is pure for 3 because the index of 3 is 2 and the
> index of 2 is 1.
>
> 4. In order for a subset of {2,3,4} to be pure for 4, 4 must be in the set.
> The only possibilities are {4}, {2,4}, {3,4} and {2,3,4}. {4} is pure for 4
> because the index of 4 is 1. {2,4} is pure for 4 because the index of 4 is 2
> and the index of 2 is 1. {3,4} is NOT pure for 4, because the index of 4 is
> 2 which is not in the set. Finally {2,3,4} is pure for 4 because the index
> of 4 is 3, the index of 3 is 2 and the index of 2 is 1. Thus the pure sets
> are {4}, {2,4} and {2,3,4}.
>
> 5. In order for a subset of {2,3,4,5} to be pure for 5, 5 must be in the
> set. Let us split into separate cases depending on the size of the set
> (1-4).
>
> The only subset of {2,3,4,5} of size 1 that contains 5 is {5}. This is pure
> for 5, because the index of 5 is 1.
>
> In any subset of {2,3,4,5} of size 2 containing 5, the index of 5 is 2. Thus
> if the set is pure, it must also contain 2, and hence must be {2,5}. This is
> pure for 5 because the index of 5 is 2 and the index of 2 is 1.
>
> In any subset of {2,3,4,5} of size 3 containing 5, the index of 5 is 3. Thus
> if the set is pure, it must also contain 3, and hence must be {2,3,5} or
> {3,4,5}. These are both pure for 5: in {2,3,5} the index of 5 is 3, the
> index of 3 is 2 and the index of 2 is 1, whereas in {3,4,5}, the index of 5
> is 3 and the index of 3 is 1.
>
> Finally the only subset of {2,3,4,5} of size 4 is {2,3,4,5} which is pure
> for 5.
>
> Thus the pure subsets of {2,3,4,5} are {5}, {2,5}, {2,3,5}, {3,4,5} and
> {2,3,4,5}.
>
> 6. Once again the set must contain 6 and be of size 1-5.
>
> If size 1, the set must be {6}, which is pure.
>
> If size 2, the set must also contain 2 and therefore must be {2,6}, which is
> pure.
>
> If size 3, the set must also contain 3 and therefore must be {2,3,6},
> {3,4,6} or {3,5,6} which are all pure.
>
> If size 4, the set must also contain 4. Furthermore the intersection of the
> set with {2,3,4} must be pure for 4, and hence must be either {4}, {2,4} or
> {2,3,4}. Since the set is a subset of {2,3,4,5,6} containing 4 and 6 with 4
> elements, it must be {3,4,5,6}, {2,4,5,6} or {2,3,4,6}. {3,4,5,6} is not
> pure for 4, and hence is not pure for 6. The others are pure.
>
> Finally, if size 5, the set must be {2,3,4,5,6}.
>
> Thus there are 8 pure sets, {6}, {2,6}, {2,3,6}, {3,4,6}, {3,5,6},
> {2,4,5,6}, {2,3,4,6} or {2,3,4,5,6}.
>
> More to follow...
>
>
> On 9 Apr 2011 09:02, "Cody" <[email protected]> wrote:
>> Respected Members,
>>
>> Hey can any one give me an example how do we get 6 for 8 and for 25
>> can any one just explain me it in small if possible.
>>
>> http://code.google.com/codejam/contest/dashboard?c=635101#s=p2
>>
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