I don't think this is the problem as his code contains:

printf("Case #%d: ",numbercount);
>

I think the problem with the first item, is not preceded with "Case #1", and
the next test cases start with a wrong count, what I mean is that, your
output looks like:

bla1 bla1
Case #1: bla2 bla2
Case #2: bla3 bla3

It should be:

Case #1: bla1 bla1
Case #2: bla2 bla2
Case #3: bla3 bla3

But I'm not sure that this is the only problem, the code is a little bit
complicated and need many performance and adjustments...



-- Amahdy AbdElAziz
http://www.linkedin.com/in/amahdyabdelaziz



On Sat, Apr 23, 2011 at 21:10, ayman bs <[email protected]> wrote:

>   it's giving error that output should start with case
>
> #1:  , eventhough my output is giving case 1#
>
>
> I didn't look at code yet :-)
>
>
>
> On Sat, Apr 23, 2011 at 8:31 AM, chase <[email protected]> wrote:
>
>> sir, my code for the problem reverse string link ::
>> http://code.google.com/codejam/contest/dashboard?c=351101#s=p1   is
>> correct , it is giving correct output on my computer , but after
>> submitting this , it's giving error that output should start with case
>> #1:  , eventhough my output is giving case 1#:   my code is  :
>>
>>
>> #include<stdio.h>
>>
>> #include<string.h>
>>
>> int main (int argc, const char * argv[]) {
>>    int n,i,j,count,check=0,end=0;
>>        int atlast,lastcheckpt,reverseprinting;
>>
>>        scanf("%d",&n);
>>                //fflush(stdin);
>>        char a[n][25];
>>        for(i=0;i<n+1;i++)
>>        {
>>                        gets(a[i]);
>>        }
>>        int numbercount=0;
>>        for(i=0;i<n+1;i++)
>>        {
>>                if(numbercount!=0){
>>                printf("Case #%d: ",numbercount);
>>                }
>>                count=(strlen(a[i]));
>>
>>                lastcheckpt=count;
>>                for(j=count;j>-1;j--)
>>                {
>>                        if(j==0){
>>
>>                                for(atlast=0;atlast<lastcheckpt;atlast++)
>>                                {
>>                                printf("%c",a[i][atlast]);
>>
>>                                        end=1;
>>
>>                                }
>>                        }
>>                        if(end==1){
>>                                break;
>>                        }
>>
>>                if(a[i][j]==' ')
>>                {
>>
>>                        check=j;
>>
>>                        if(lastcheckpt==count)
>>                        {
>>
>>
>>  for(reverseprinting=(check+1);reverseprinting<(lastcheckpt
>> +1);reverseprinting++)
>>                             {
>>
>>
>>                        printf("%c",a[i][reverseprinting]);
>>                        }
>>                        }
>>                        else
>>                        {
>>                                for(reverseprinting=(check
>> +1);reverseprinting<(lastcheckpt);reverseprinting++)
>>                                {
>>                                        printf("%c",a[i][reverseprinting]);
>>
>>                                }
>>                        }
>>
>>                        printf(" ");
>>
>>
>>                        lastcheckpt=check;
>>                }
>>
>>                }
>>                end=0;
>>
>>
>>                printf("\n");
>>                numbercount++;
>>
>>        }
>> }
>>
>> --
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>>
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