Hello
Can anybody kindly upload prob C output or let me know how my output is
wrong ?
Am sure my logic is right. [Comparing xor's of the 2 divided group such that
they are same and printing highest such possible sum as value]
Reg, robin.


On Sun, May 8, 2011 at 12:50 PM, vivek dhiman <[email protected]>wrote:

> Lucky!
>
> You are right.
>
> if xor of two lists is same. (say xor1 = xo2)
>
> So the exor of these two wil be 0  (xor (xor1,xor2) = 0)
> Or in other words lists can be divided if the xor of all the elements is
> zero.
>
> :)
>
>
>
>
> On Sun, May 8, 2011 at 8:17 AM, keshav agarwal <[email protected]>wrote:
>
>> please tell me of my logic was correct or i just got lucky to get it
>> correct
>>
>> if xor to a list of nos. is zero only then the division is possible
>> in this case patrick can be given the one candy with lowest value while
>> sean keeps the rest
>>
>> if      xor(n nos.)=0
>> then       (nth no.) xor (xor of n-1 nos.)=0
>>
>> so patrick gets the nth candy and sean keeps the rest
>>
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>
>
>
> --
> Regards
> Vivek Dhiman
>
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