>
> k=++j + (++j + ++j); it gives 15!
>
As explained before, here is the compiler behavior that lead to this output:
j=2
Divide the long expression into two branches: ++j AND (++j + ++j)
The first branch: j=j+1, then the result is found in j
The second branch: divide into two subbranches, ++j AND ++j
The first branch: j=3 and its result is found in j
The second branch:
The first subbranch: j=j+1, then the result is found in j
The second subbranch: j=j+1, then the result is found in j
The first branch: j=3 and its result is found in j
The second branch:
The first subbranch: j=4 and its result is found in j
The second subbranch: j=5 and its result is found in j
The first branch: j=5
The second branch: Add(The first subbranch: {j=5} , The second
subbranch:{j=5}), which gives 10
*The result:* Add(The first branch: {j=5}, 10), which gives 15
I agree, and the 'deep language specification' here is that this
> behaviour is undefined.
>
Maybe you are correct here, it's neither a bug nor as designed, it's just
undefined, which means that other behavior could be taken under different
machines, and thus different results.
-- Amahdy
www.amahdy.net
On Tue, Aug 16, 2011 at 12:09, Paul Smith <[email protected]> wrote:
> On Tue, Aug 16, 2011 at 1:03 AM, Amahdy <[email protected]> wrote:
> > I don't agree with you +Paul, one of the essential learning curves IMHO,
> is
> > to learn the compiler behavior and the deep language specifications and
> > details.
>
> I agree, and the 'deep language specification' here is that this
> behaviour is undefined.
>
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