But this code will work:
#include <stdio.h>
>
> int main()
> {
> int i;
> int array[]={ 2, 4, 45, 3, 21};
>
> *i = 9;*
> for ( ;i < sizeof(array);){
> printf("%d\n",array[3]);
> i++;
> }
> return 0;
>
> }
>
*sizeof* is a keyword BTW, and it's designed to return a value of type *
size_t*. It must be a number greater than or equal *zero* because it
represents a size of something, which could never be negative.
In *gcc* compiler implementation, *size_t* is actually a *long unsigned int*
.
In the for loop, you are trying to compare an unsigned value with a negative
(signed) value, it won't work and the signed value get transformed into a
very big number (because of reading it without the -ve sign).
A solution for this could be a simple casting to *int* for example:
for ( ;i < *(int)* sizeof(array);){
>
-- Amahdy
www.amahdy.net
On Tue, Aug 30, 2011 at 17:42, addytheboss khandalkar <
[email protected]> wrote:
> hello friends,
>
> i am facing trouble in understanding how does this code works and how does
> sizeof( ) works? and why it is not entering in the loop ?
>
>
>
> #include <stdio.h>
>
> int main()
> {
> int i;
> int array[]={ 2, 4, 45, 3, 21};
>
> i = -9;
>
> for ( ;i < sizeof(array);){
> printf("%d\n",array[3]);
> i++;
> }
>
> }
>
>
>
> Thanks
> Addytheboss
>
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