Hi Nikhil,
I think this piece of code might be closer to what you are thinking :)
#include<stdio.h>
int main() {
int i=0;
int length=0, sum=0;
char the_string[200];
int the_array[200];
//memset(the_string, 0x0, 200*sizeof(char));
scanf("%s", the_string);
while(the_string[i]!='\0') {
i++;
}
length = i;
for(i=0; i<length; i++) {
the_array[i] = the_string[i] - 0x30;
}
/* Now the_array contains the numbers inside the_string */
for(i=0; i<length; i++) {
sum += the_array[i];
}
printf("%d\n", sum);
return 0;
}
Regards,
Vikram
On Wed, Dec 21, 2011 at 10:00 AM, Amir Hossein Sharifzadeh <
[email protected]> wrote:
> I believe that's impossible.
>
>
>
> On Wed, Dec 21, 2011 at 3:34 AM, Nikhil <[email protected]>wrote:
>
>> ok
>> using loop but without using any predifine functioin. What would be
>> the best answer of the problem???
>>
>> On Dec 19, 7:00 am, Vikram Gaur <[email protected]> wrote:
>> > hmm... by using lambda functions and map() in python, we can find the
>> > sum without actually using a loop.
>> >
>> > Here's my code:
>> >
>> > #!/usr/bin/python
>> > def f(item): return int(item);
>> >
>> > print sum(map(f,list(raw_input().strip())))
>> >
>> > On 12/19/11, Bruno Oliveira <[email protected]> wrote:
>> >
>> > > I think it can be done via functional programming and by using lambda
>> > > functions and lists by comprehension
>> >
>> > > --
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>> >
>> > --
>> > Thanks and Regards
>> > Vikram Gaur
>> > Software Engineer
>> > Samsung Engineering Labs, Noida
>> > +91-9818540102
>> >
>> > "Since human beings themselves are not fully debugged yet, there will be
>> > bugs in your code no matter what you do." - Chris Mason
>>
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Thanks and Regards
Vikram Gaur
Software Engineer
Samsung Engineering Labs, Noida
+91-9818540102
"Since human beings themselves are not fully debugged yet, there will be
bugs in your code no matter what you do." - Chris Mason
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