updated
Start:
All choices for the malt are moved the end if the choice list
ex:3 1,2 0,1 0 given
2 0,2 0,3 1 arranged is the pre condition for this algorithm
For each test case
declare malt and unmalt of size number of flavours,initial values of malt
and unmalt are zeros
1)get all cutomer choices in to choices
2)customer's who have only one choice have to be full filled
if unmalt flavour i is the only choices of the customer then increment the
value of the unmalt[i]+=1
if malt flavour i is the only choices of the customer then increment the
value of the malt[i]+=1
3)check if any flavour i is malted and unmalted,then return "IMPOSSIBLE"
4)Otherwise check the customers who are having more then one choices
for each choices either malted or unmalted at least one should satisfy
below condition
ex:3 1 flavour 3 malted
if malt[3]==0 and unmalt[3]==0 then this customer chilce can be satified
malt[i]+=1
if unmalt[3]>0 this choice can not be satified
ex:3 0 flavour 3 unmalted
if malt[3]==0 and unmalt[3]==0 then this customer chilce can be satified
if malt[3]>0 this choice can not be satified
5)at least one of the each customer choice are satisfied according to the
step 4
then print all malt[i] if malt[i]>0 print 1 else 0
End:

On Sat, Apr 7, 2012 at 5:08 PM, Samuel Jawahar <[email protected]> wrote:

> Hello Bartholomew
> I have solved the Milkshake(
> http://code.google.com/codejam/contest/dashboard?c=32016#s=p1&a=1)
> problem with below algorithm
> Start:
> For each test case
> declare malt and unmalt of size number of flavours,initial values of malt
> and unmalt are zeros
> 1)get all cutomer choices in to choices
> 2)customer's who have only one choice have to be full filled
> if unmalt flavour i is the only choices of the customer then increment the
> value of the unmalt[i]+=1
> if malt flavour i is the only choices of the customer then increment the
> value of the malt[i]+=1
> 3)check if any flavour i is malted and unmalted,then return "IMPOSSIBLE"
> 4)Otherwise check the customers who are having more then one choices
> for each choices either malted or unmalted at least one should satisfy
> below condition
> ex:3 1 flavour 3 malted
> if malt[3]==0 and unmalt[3]==0 then this customer chilce can be satified
> malt[3]+=1
> if unmalt[3]>0 this choice can not be satified
> ex:3 0 flavour 3 unmalted
> if malt[3]==0 and unmalt[3]==0 then this customer chilce can be satified
> unmalt[i]+=1
> if malt[3]>0 this choice can not be satified
> 5)at least one of the each customer choice are satisfied according to the
> step 4
> then print all malt[i] if malt[i]>0 print 1 else 0
> End:
> i am getting incorrect answer can you please have a look on my algorithm
> Regards
> Samuel
>
> On Wed, Apr 4, 2012 at 10:19 PM, Bartholomew Furrow <[email protected]>wrote:
>
>> Your numbers are a bit low for input and output files -- we let those get
>> as high as 200kB (the input files can actually be bigger, but max out at
>> 200kB gzipped -- all modern browsers [as far as I can tell] automatically
>> request a gzipped version from the server).  Bala, for my own information,
>> how fast is your connection in kB/s?
>>
>>
>> On Wed, Apr 4, 2012 at 4:58 AM, Amahdy <[email protected]> wrote:
>>
>>> At the beginning of the competition, due to the very heavy load and
>>> number of people loading the competition page, there may be a delay not due
>>> to your internet but due to Google's server load. (Specially in Round1 (A,
>>> B, & C))
>>> But other than that, you need to load the question page once (~ 2K),
>>> download the input files (~5K) and upload yours (~ 5K also). Which I assume
>>> is good enough over 2G.
>>>
>>> p.s. There should be an improvement in the Google's server load, so
>>> maybe you won't even encounter the firstly mentioned problem.
>>>
>>> -- AMahdy!
>>> www.amahdy.net
>>>
>>>
>>>
>>> On Wed, Apr 4, 2012 at 13:12, bala subramanian 
>>> <[email protected]>wrote:
>>>
>>>> Hi I am using 2g network only.its enough for google code jam or we
>>>> need high speed for gcj.please give me solution.
>>>>
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