I appreciate your input Bruno. I did figured it out later on, however, I 
should have paid more attention to the mathematical definition, and rely 
less on the text description of the problem :)
Take care,
Merg
On Sunday, April 15, 2012 1:13:53 PM UTC-4, BrunoOliveira wrote:
>
> Hey merg,
>
> In fact, 10 and 40 are not m and n but yes A and B.
>
> That means you have 3 distinct pairs of recycled numbers between 10 and 40 
> which are very easily caught by hand:
>
> 12,21
> 13,31
> 23,32
>
> 10 and 40 are not a pair of recycled numbers in this case. Also, there can 
> be no leading zeroes.
>
> On Sat, Apr 14, 2012 at 7:11 PM, Merg <[email protected]> wrote:
>
>> Hello,
>>
>> Can someone please elaborate a bit further on problem C?
>>
>> When the problem states "a pair of distinct positive integers (n, m)
>> is recycled if you can obtain m by moving some digits from the back of
>> n"
>>
>> How can we obtain 40 (m) by moving 0 (back of n) from 10 (n)?
>>
>> 10 40      Case #2: 3
>>
>> Thanks in advance for your help.
>>
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