One thing that was not mentioned is that it is never needed to press backspace for over (B-A)/2 times as that will always be more than B+2.
On May 1, 6:56 am, jitendra <[email protected]> wrote: > import java.util.*; > > class A { > static Scanner scan; > public static double solve() { > int a = scan.nextInt(); > int b = scan.nextInt(); > double res = 2+b; > double p = 1; > for(int x=1;x<=a;x++) { > double f = scan.nextDouble(); > p *= f; > int v = b+a+1-2*x; > double r2 = p*v+(1-p)*(v+b+1); > if(res>r2) res=r2; > } > return res; > } > public static void main(String[] args) { > scan = new Scanner(System.in); > int n = scan.nextInt(); > for(int i=1;i<=n;i++) { > System.out.print("Case #"+i+": "); > System.out.println(solve()); > } > } > > } > > i can not get > > double res = 2+b; > double p = 1; > and > int v = b+a+1-2*x; > double r2 = p*v+(1-p)*(v+b+1); > if(res>r2) res=r2; > > parts pls explain in detail ....... any answers and links are appreciable > ........ > > A.java > < 1KViewDownload -- You received this message because you are subscribed to the Google Groups "Google Code Jam" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/google-code?hl=en.
