I will like to hear others opinions.

But this was a pretty straight forward problem. As from the problem
statements:
"*You may assume that: *

   - *If there is an inheritance path from X to Y then there is no
   inheritance path from Y to X.*
   - *A class will never inherit from itself*."

This implies that the graph was directed.
So to solve this you just do a BFS of the graph and as soon as you revisit
any already visited node for the first time, just stop BFS and say that
this has a diamond. which is nothing but a loop.

Regards
Vivek Dhiman

On Mon, May 7, 2012 at 12:48 PM, Satyajit Bhadange <
[email protected]> wrote:

> Considering the case : A inherits from B C D,
> B and C inherits from E.
>
> In this case Diamond is formed between A B C E. hence >=2 outdegree
>
> On Mon, May 7, 2012 at 12:41 PM, Manmeet Singh <[email protected]>wrote:
>
>> why more than 2, even 2 is ok
>>
>> On Mon, May 7, 2012 at 11:34 AM, Satyajit Bhadange <
>> [email protected]> wrote:
>>
>>>
>>> During the contest my first attempt for solving the problem was to find
>>> the class having more than tow out degrees.
>>> Starting from this class i apply union and find algorithm (which is use
>>> to detect cycle while constructing minimum spanning tree).
>>>
>>> This algorithm didnt work. I am still not getting why this would fail ?
>>>
>>> Can anyone please tell me why this would fail.
>>>
>>> Thanks & Regards,
>>> *Satyajit Bhadange
>>> Software Programmer*
>>>
>>> *Problems & Solutions* <http://www.satyajit-algorithms.com>
>>>
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>
>
>
> --
>
> Thanks & Regards,
> *Satyajit Bhadange
> Software Programmer*
>
> *Problems & Solutions* <http://www.satyajit-algorithms.com>
>
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-- 
Regards
Vivek Dhiman

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