If it is impossible to make a profit given the market trends, you should
output IMPOSSIBLE.



On 22 January 2013 17:36, Satyajit Bhadange <[email protected]>wrote:

> if(min>m)
>     {
>         System.out.println("IMPOSSIBLE");
>     }
>
> for which case ?
>
>
> On Tue, Jan 22, 2013 at 5:25 PM, mandeep khatkar <[email protected]>wrote:
>
>> someone plz modify this code i am getting an error "your output should
>> start with Case #1:"
>> and here is the link to problem
>> http://code.google.com/codejam/contest/837485/dashboard#s=p1
>> and below is my solution...thanks in advance...
>>
>> package chef;
>>
>> import java.io.BufferedReader;
>> import java.io.IOException;
>> import java.io.InputStreamReader;
>> import java.util.StringTokenizer;
>>
>> /*
>>  * To change this template, choose Tools | Templates
>>  * and open the template in the editor.
>>  */
>>
>> /**
>>  *
>>  * @author Pardeep
>>  */
>> public class chefworld {
>>     static int len=12;
>>
>>     static BufferedReader br=new BufferedReader(new
>> InputStreamReader(System.in));
>>
>>     static StringTokenizer st;
>>
>>     public static void main(String a[]) throws IOException
>>    {
>>     int n=Integer.parseInt(br.readLine());
>>
>>     for(int j=1;j<=n;j++)
>>     {
>>            int m=Integer.parseInt(br.readLine());
>>     //System.out.println("value of m is:"+m);
>>     int max,min,minpos=0,maxpos=0;
>>     int arr[]=new int[len];
>>     int profit=0;
>>     st=new StringTokenizer(br.readLine());
>>     for(int i=0;st.hasMoreTokens();i++)
>>     {
>>         arr[i]=Integer.parseInt(st.nextToken());
>>        // System.out.println(i+"element is"+arr[i]);
>>     }
>>     min=(max=arr[0]);
>>     //System.out.println(min+" "+max);
>>     //max=min;
>>     for(int i=1;i<len-1;i++)                             //to find max
>> element and it's position
>>     {
>>         if(max<=Math.max(arr[i], arr[i+1]))
>>         {
>>             max=Math.max(arr[i], arr[i+1]);
>>             if(max==arr[i])
>>             {
>>                 maxpos=i;
>>             }
>>             else
>>             {
>>                 maxpos=i+1;
>>             }
>>         }
>>
>>     }
>>     for(int i=0;i<maxpos;i++)                           //to find minimum
>> element and its position
>>     {
>>         if(min>=Math.min(arr[i], arr[i+1]))
>>         {
>>             min=Math.min(arr[i], arr[i+1]);
>>             if(min==arr[i])
>>             {
>>                 minpos=i;
>>             }
>>             else
>>             {
>>                 minpos=i+1;
>>             }
>>         }
>>     }
>>     if(min>m)
>>     {
>>         System.out.println("IMPOSSIBLE");
>>     }
>>     else
>>     {
>>         int d=m/arr[minpos];
>>         profit=d*(arr[maxpos]-arr[minpos]);
>>         System.out.println("Case #"+j+": "+(minpos+1)+" "+(maxpos+1)+"
>> "+" "+profit);
>>     }
>>     }
>>     //System.out.println("min is: "+min+"pos is:"+minpos+" "+"max is
>> "+max+"pos is"+maxpos);
>>    System.exit(0);
>>
>>    }
>> }
>>
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>>
>>
>
>
>
> --
>
> Thanks & Regards,
> *Satyajit Bhadange
> Software Programmer*
>
> *Problems & Solutions* <http://www.satyajit-algorithms.com>
>
> --
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>
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