The problem statement is very clear on when he is a bad magician. From the
problem statement:

>If there are multiple cards the volunteer could have chosen, y should be
"Bad magician!"

So it doesn't matter if in real life that would be a bad magician. In the
problem it's only a bad magician only in that case.


On Sun, Apr 13, 2014 at 8:54 AM, newbie007 <[email protected]> wrote:

> Hi,
>
> If in the second arrangement, the cards from the first chosen row are not
> all in different rows, then he IS a Bad magician!
> I know that the magician may be luck and still be able to find the card
> depending on the volunteer choices, but it doesn't change the fact that he
> IS a Bad magician!
>
> For me this is not a corner case. It is one thing that was not clear in
> the problem, so it should be covered in the sample cases.
>
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