Hi Emil,

Thanks for your efforts, in this regard. I used Xcode and the latest Macbook 
Pro...Yes, I agree with you. It is just a matter of notation. As Alara has 
pointed out the differences are very small, smaller than their tolerance level 
mentioned... 

I think I have to wait for chance, next year...!

On Wednesday, April 16, 2014 12:31:58 PM UTC-4, Emil Maskovsky wrote:
> I tried to build and run your code on my inputs and your program is giving me 
> correct results (or at least the same as my accepted results) for both small 
> and large. The direct conversion from float to int should be the same as 
> floor() in the principle (for non-negative results, and the negative results 
> are ignored anyway) ... although the ceil(...)-1 should be more correct, as I 
> mentioned before (floor will give you n+1 in the cases, where both n and n+1 
> will supply the same result), but the n is actually not required and the time 
> should be the same, so it should not matter.
> 
> 
> 
> Which compiler (and version) did you use to compile the program, and under 
> which operating system?
> 
> 
> 
> 
> 
> On Tuesday, April 15, 2014 11:54:54 PM UTC+2, Sivasathivel Kandasamy wrote:
> 
> > Hi guys,
> 
> > 
> 
> > 
> 
> > 
> 
> > Thanks for the response...
> 
> > 
> 
> > Here is the code:
> 
> > 
> 
> > 
> 
> > 
> 
> > #include <iostream>
> 
> > 
> 
> > #include <fstream>
> 
> > 
> 
> > #include <ctime>
> 
> > 
> 
> > #include <time.h>
> 
> > 
> 
> > #include <iomanip>
> 
> > 
> 
> > 
> 
> > 
> 
> > #define CPS 2
> 
> > 
> 
> > 
> 
> > 
> 
> > using namespace std;
> 
> > 
> 
> > 
> 
> > 
> 
> > 
> 
> > 
> 
> > int main(int argc, const char * argv[])
> 
> > 
> 
> > {
> 
> > 
> 
> > 
> 
> > 
> 
> >     ifstream infile("input2.in"); //I renamed the google input file for 
> > simplicity
> 
> > 
> 
> >     ofstream outfile("output.out");
> 
> > 
> 
> >     
> 
> > 
> 
> >     int nCases;
> 
> > 
> 
> >     infile >> nCases;
> 
> > 
> 
> >     cout<<"# Cases: "<<nCases<<endl;
> 
> > 
> 
> >     
> 
> > 
> 
> >     for (int ci = 0; ci < nCases; ci++) {
> 
> > 
> 
> >         double C, F, X;
> 
> > 
> 
> >         infile >> C;
> 
> > 
> 
> >         infile >> F;
> 
> > 
> 
> >         infile >> X;
> 
> > 
> 
> >         
> 
> > 
> 
> >         int n = (X/C) - (CPS/F);
> 
> > 
> 
> >         if (n < 0) {
> 
> > 
> 
> >             n = 0;
> 
> > 
> 
> >         }
> 
> > 
> 
> >         double tn = 0;//Time Taken to by nFarms
> 
> > 
> 
> >         for (int i=1; i <=n; i++) {
> 
> > 
> 
> >             tn += C/(CPS+((i-1)*F));
> 
> > 
> 
> >         }
> 
> > 
> 
> >         double tw = tn + X/(CPS+n*F);
> 
> > 
> 
> > 
> 
> > 
> 
> >         cout<<"Case #"<<std::fixed<< std::setprecision(7)<<ci+1<<": 
> > "<<tw<<endl;
> 
> > 
> 
> >         outfile<<"Case #"<<ci+1<<": "<<std::fixed<< 
> > std::setprecision(7)<<tw<<endl;
> 
> > 
> 
> >     }
> 
> > 
> 
> >     infile.close();
> 
> > 
> 
> >     outfile.close();
> 
> > 
> 
> >     return 0;
> 
> > 
> 
> > }
> 
> > 
> 
> > 
> 
> > 
> 
> > 
> 
> > 
> 
> > Could any one spot any problem?
> 
> > 
> 
> > 
> 
> > 
> 
> > Thanks in Advance,
> 
> > 
> 
> > 
> 
> > 
> 
> > Regards,
> 
> > 
> 
> > 
> 
> > 
> 
> > 
> 
> > 
> 
> > On Monday, April 14, 2014 1:36:23 PM UTC-4, Jugesh Sundram wrote:
> 
> > 
> 
> > > Hi Siva, 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > Can you post your code so that we can have a closer inspection?
> 
> > 
> 
> > > 
> 
> > 
> 
> > > Thanks
> 
> > 
> 
> > > 
> 
> > 
> 
> > > On Apr 14, 2014 1:24 PM, "Sivasathivel Kandasamy" 
> > > <[email protected]> wrote:
> 
> > 
> 
> > > 
> 
> > 
> 
> > > I attempted the second problem, which took all the time irrespective of 
> > > my confidence in my logic. I mean I tested my algorithm with the samples 
> > > given in the problem page and was able to get answers correct to the last 
> > > decimal. However, when I used their input and produced the output, Google 
> > > Code Jam didn't accept my outputs. I'm totally at loss where the problem 
> > > was... And I posted the problem in Stack Exchange, where many seems to 
> > > agree with my logic.
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > Losing the qualification round is painful, but I would be worth it if I 
> > > could know where I went wrong...
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > Here is the logic I came with... (with some algebra...):
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > Let us assume, n as the minimum number of Farms to buy to win in the 
> > > shortest time. n is a non-negative integer value.
> 
> > 
> 
> > > 
> 
> > 
> 
> > > a is the number of cookies one gets per second, a=2;
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > n is the minimum number of farms to buy to win, if and only if the 
> > > following equation is satisfied...
> 
> > 
> 
> > > 
> 
> > 
> 
> > > i.e time taken to buy n−1 farms + time to reach goal with (n−1) Farms > 
> > > time taken to buy n farms + time to reach goal with n Farms
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > However, time taken to buy n Farms =∑C/(a+(i−1)F); i = 1,...,n
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > Therefore LHS becomes:
> 
> > 
> 
> > > 
> 
> > 
> 
> > > (∑C/(a+(i−1)F))+(X/(a+(n−1)F))
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > RHS becomes
> 
> > 
> 
> > > 
> 
> > 
> 
> > > (∑C/(a+(i−1)F))+(X/(a+nF))+C/(a+(n−1)F)
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > by rearranging the equations,
> 
> > 
> 
> > > 
> 
> > 
> 
> > > (X/(a+(n−1)F))>(X/(a+nF))+(C/(a+(n−1)F))(eq.1)
> 
> > 
> 
> > > 
> 
> > 
> 
> > > (X/(a+(n−1)F))−(X/(a+nF))>(C/(a+(n−1)F))
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > After some rearrangements, it becomes:
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > XF/(a+nF)>C
> 
> > 
> 
> > > 
> 
> > 
> 
> > > XF>C(a+nF)
> 
> > 
> 
> > > 
> 
> > 
> 
> > > XF/C>a+nF
> 
> > 
> 
> > > 
> 
> > 
> 
> > > (XF/C)−a>nF
> 
> > 
> 
> > > 
> 
> > 
> 
> > > (1/F)((XF/C)−a)>n
> 
> > 
> 
> > > 
> 
> > 
> 
> > > (X/C)−(a/F)>n
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > or
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > n <(X/C)−(a/F)
> 
> > 
> 
> > > 
> 
> > 
> 
> > > --- by ensuring that n is an non-negative integer, this equation would 
> > > give the minimum number of farms,n, to buy. Assuming it is not possible 
> > > to buy fraction of farms
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > With n Farms, the total time taken to reach the goal would be given by 
> > > RHS of (eq.1)
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > Could anyone tell me, where I went wrong?
> 
> > 
> 
> > > 
> 
> > 
> 
> > > As I sample, I tried with the samples and produced results correct to the 
> > > last decimal...!
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > --
> 
> > 
> 
> > > 
> 
> > 
> 
> > > You received this message because you are subscribed to the Google Groups 
> > > "Google Code Jam" group.
> 
> > 
> 
> > > 
> 
> > 
> 
> > > To unsubscribe from this group and stop receiving emails from it, send an 
> > > email to [email protected].
> 
> > 
> 
> > > 
> 
> > 
> 
> > > To post to this group, send email to [email protected].
> 
> > 
> 
> > > 
> 
> > 
> 
> > > To view this discussion on the web visit 
> > > https://groups.google.com/d/msgid/google-code/5d9cb132-96d9-43df-9a82-3705895148d4%40googlegroups.com.
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > For more options, visit https://groups.google.com/d/optout.
> 
> > 
> 
> > 
> 
> > 
> 
> > 
> 
> > 
> 
> > 
> 
> > 
> 
> > On Monday, April 14, 2014 1:36:23 PM UTC-4, Jugesh Sundram wrote:
> 
> > 
> 
> > > Hi Siva, 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > Can you post your code so that we can have a closer inspection?
> 
> > 
> 
> > > 
> 
> > 
> 
> > > Thanks
> 
> > 
> 
> > > 
> 
> > 
> 
> > > On Apr 14, 2014 1:24 PM, "Sivasathivel Kandasamy" 
> > > <[email protected]> wrote:
> 
> > 
> 
> > > 
> 
> > 
> 
> > > I attempted the second problem, which took all the time irrespective of 
> > > my confidence in my logic. I mean I tested my algorithm with the samples 
> > > given in the problem page and was able to get answers correct to the last 
> > > decimal. However, when I used their input and produced the output, Google 
> > > Code Jam didn't accept my outputs. I'm totally at loss where the problem 
> > > was... And I posted the problem in Stack Exchange, where many seems to 
> > > agree with my logic.
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > Losing the qualification round is painful, but I would be worth it if I 
> > > could know where I went wrong...
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > Here is the logic I came with... (with some algebra...):
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > Let us assume, n as the minimum number of Farms to buy to win in the 
> > > shortest time. n is a non-negative integer value.
> 
> > 
> 
> > > 
> 
> > 
> 
> > > a is the number of cookies one gets per second, a=2;
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > n is the minimum number of farms to buy to win, if and only if the 
> > > following equation is satisfied...
> 
> > 
> 
> > > 
> 
> > 
> 
> > > i.e time taken to buy n−1 farms + time to reach goal with (n−1) Farms > 
> > > time taken to buy n farms + time to reach goal with n Farms
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > However, time taken to buy n Farms =∑C/(a+(i−1)F); i = 1,...,n
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > Therefore LHS becomes:
> 
> > 
> 
> > > 
> 
> > 
> 
> > > (∑C/(a+(i−1)F))+(X/(a+(n−1)F))
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > RHS becomes
> 
> > 
> 
> > > 
> 
> > 
> 
> > > (∑C/(a+(i−1)F))+(X/(a+nF))+C/(a+(n−1)F)
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > by rearranging the equations,
> 
> > 
> 
> > > 
> 
> > 
> 
> > > (X/(a+(n−1)F))>(X/(a+nF))+(C/(a+(n−1)F))(eq.1)
> 
> > 
> 
> > > 
> 
> > 
> 
> > > (X/(a+(n−1)F))−(X/(a+nF))>(C/(a+(n−1)F))
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > After some rearrangements, it becomes:
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > XF/(a+nF)>C
> 
> > 
> 
> > > 
> 
> > 
> 
> > > XF>C(a+nF)
> 
> > 
> 
> > > 
> 
> > 
> 
> > > XF/C>a+nF
> 
> > 
> 
> > > 
> 
> > 
> 
> > > (XF/C)−a>nF
> 
> > 
> 
> > > 
> 
> > 
> 
> > > (1/F)((XF/C)−a)>n
> 
> > 
> 
> > > 
> 
> > 
> 
> > > (X/C)−(a/F)>n
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > or
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > n <(X/C)−(a/F)
> 
> > 
> 
> > > 
> 
> > 
> 
> > > --- by ensuring that n is an non-negative integer, this equation would 
> > > give the minimum number of farms,n, to buy. Assuming it is not possible 
> > > to buy fraction of farms
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > With n Farms, the total time taken to reach the goal would be given by 
> > > RHS of (eq.1)
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > Could anyone tell me, where I went wrong?
> 
> > 
> 
> > > 
> 
> > 
> 
> > > As I sample, I tried with the samples and produced results correct to the 
> > > last decimal...!
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > --
> 
> > 
> 
> > > 
> 
> > 
> 
> > > You received this message because you are subscribed to the Google Groups 
> > > "Google Code Jam" group.
> 
> > 
> 
> > > 
> 
> > 
> 
> > > To unsubscribe from this group and stop receiving emails from it, send an 
> > > email to [email protected].
> 
> > 
> 
> > > 
> 
> > 
> 
> > > To post to this group, send email to [email protected].
> 
> > 
> 
> > > 
> 
> > 
> 
> > > To view this discussion on the web visit 
> > > https://groups.google.com/d/msgid/google-code/5d9cb132-96d9-43df-9a82-3705895148d4%40googlegroups.com.
> 
> > 
> 
> > > 
> 
> > 
> 
> > > 
> 
> > 
> 
> > > For more options, visit https://groups.google.com/d/optout.

-- 
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