Hi,

I tried the problem for practice and got correct answers to all but one of the 
small input test cases using a greedy strategy.

B-small-practice.in Case #38

Input:
3 2 6
1 2
1 1
3 1
2 2
2 1
3 2

Output (I got: 3 1)
3 0

My code is at https://ideone.com/Q6rnSx

Unnecessary promotion occurs due to the seat assignment:
Ride 1 = Seat 1: Customer 1 + Seat 2: Customer 2
Ride 2 = Seat 1: Customer 2 + Seat 2: Customer 1
Ride 3 = Seat 3: Customer 1 + Seat 3: Customer 2 (one of the seats need to be 
promoted)

Can avoid this with the following seat assignment:
Ride 1 = Seat 1: Customer 1 + Seat 2: Customer 2
Ride 2 = Seat 1: Customer 2 + Seat 2: Customer 3
Ride 3 = Seat 1: Customer 3 + Seat 2: Customer 1

I would appreciate either a simple fix for my greedy solution if possible or a 
different working greedy solution.

Thanks

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