Joseph,

That's not the DP approach. That's the smarter-than-DP approach as
described in the analysis page.

On Mon, Apr 16, 2018, 11:31 Joseph DeVincentis <[email protected]> wrote:

> As I solved this problem, I noted that the range of dimensions for the
> cookies was limited to 1 to 250. This interval is less than sqrt(2)^16, and
> I realized it meant that if you keep track of the intervals, merging them
> as they overlap, you will never have too many different intervals.
>
> Start with a single interval, [P,P] where P is the sum of the perimeters
> of all uncut cookies.
> Now process the cookies in turn, from smallest to largest.
> Suppose your smallest cookie is 1x1. Then you end up with two intervals,
> [P,P] and [P+2,P+2sqrt(2)].
> Now if the next cookie has min(W,H) < sqrt(2) (that is, since the
> dimensions are integers, if it has either dimension 1), then the range it
> creates will overlap with this one. So it if was 1x2, then you would have a
> range [P+2,P+2sqrt(5)] which overlaps with the previous one completely,
> eliminating it, and a new range [P+4,P+2sqrt(2)+2sqrt(5)], which also
> overlaps since 4 < 2sqrt(5), so after this step you only have [P,P] and
> [P+2,P+2sqrt(2)+sqrt(5)].
>
> It is possible for the number of intervals to grow if the cookie sizes are
> more different. For instance, if the second-smallest cookie was 2x2, then
> you'd get an interval of [P+4, P+4sqrt(2)] from it, as well as [P+6,
> P+6sqrt(2)] when both offsets are applied. 4sqrt(2) is about 5.66 so none
> of these intervals overlap, and we have 4 intervals for the next cookie.
>
> However, if you want to keep your intervals from crashing with these, the
> next cookie's smaller dimension must be at least 3sqrt(2), and since they
> are integers, it must be at least 5. Even so, if it is 5, and you add the
> interval [P+10, P+10sqrt(2)], when you add the other intervals when this
> cut and some of the others are made, the [P+12, P+12sqrt(2)] and [P+14,
> P+14sqrt(2)] crash with the P+10 interval, and those crash with the [P+16,
> P+16sqrt(2)] interval, so we have actually only added one more interval
> [P+10,P+16sqrt(2)] in this step.
>
> For your next cookie to not stomp on the intervals you have already made,
> the next cookie has to have minimum dimension larger than 8sqrt(2), or as
> an integer at least 12. And this again makes a new interval which does not
> overlap the 5 existing ones, but the other intervals it makes when it
> combines with the other existing intervals will all overlap, so you'll get
> one new interval [P+24, P+40sqrt(2)].
>
> Because the other intervals are quite close together compared with the
> size of the new interval we are adding, this will happen no matter how
> large we make the next interval. If we instead add more small intervals, we
> will quickly fill in the gaps between the intervals and just have one large
> interval. And because we can only grow to 250 times the size of the
> smallest cookie, we can only do a few of these steps, each of which more
> than doubles the size of the previous cookie, before we reach the size of
> the largest allowed cookie.
>
> In my example, the next cookie size that will not overlap with the
> existing intervals is 29x29, making an interval [P+58, P+98sqrt(2)]. The
> next is 70, making an interval [P+140, P+238sqrt(2)]. The next is 169,
> making an interval [P+338, P+576sqrt(2)]. And the next required size is too
> large. As a result, you never actually have more than 9 intervals! It
> doesn't matter that you can have 100 different-sized cookies, because you
> will only ever have a handful of separate reachable intervals of perimeter,
> and you can maintain the list of these intervals until one of them includes
> the solution - at which point you stop and give the exact desired perimeter
> as your solution - or none of them ever does, and when you get through the
> whole list you can report the maximum of the largest interval less than the
> goal.
>
> This is exactly what my solution does, keeping track of a list of
> intervals of accessible perimeters after adding a cut in each cookie to the
> possible solutions, inserting the new interval properly in the list (after
> the interval which starts before it), checking to see if it overlaps the
> previous interval and any number of following intervals, and merging all
> such overlapping intervals into one new one. Because the list of intervals
> actually never exceeds length 9, you don't even need to program a binary
> search to efficiently find the right place to insert each new interval.
> You'll be inserting fewer than 900 intervals in a list that, due to
> merging, never gets longer than 9, and you can traverse the whole list of
> intervals each time looking for the right insertion point.
>
>
>
>
> On Sat, Apr 14, 2018 at 2:51 PM, Artem Voronin <[email protected]
> > wrote:
>
>> Hey,
>>
>> Can someone clarify this description of dp approach?
>>
>> "For each cookie, we are deciding whether to leave it as is, or cut it,
>> which adds L to our total perimeter and gives us up to R - L units of
>> additional "slack". Once we have finished deciding which cookies to cut, we
>> can include as much or as little of this "slack" as we want. All other
>> things being equal, having more slack is always better for us."
>>
>> What is the state of dp here ?
>> if it's (remaning_p, index, slack) then how to deal with fact that slack
>> has double type and it seems it can have exponential number of different
>> values?
>> if it's (remaning_p, index) then it seems we need to iterate in range [0;
>> R - L] inside each state as we can't be greedy and use R-L value only for
>> example.
>>
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