On Tuesday, April 2, 2019 at 9:31:52 PM UTC+5:30, Andy wrote:
> aren't all these numbers on the same line?
>
>
> On Tue, Apr 2, 2019 at 11:15 PM <[email protected]> wrote:
> Hello Everyone,
>
> I am facing run time errors in the trouble sort program. I don't know why. I
> have tried to cover all the aspects asked. Kindly help me. My code is written
> in Java.
>
> The link for the problem is:
> https://codingcompetitions.withgoogle.com/codejam/round/00000000000000cb/00000000000079cb
>
>
>
> My Code is:
>
>
> for(i=0;i<n;i++)
>
> {
>
> ar[i]=Integer.parseInt(in.readLine());
>
> }
>
According to your advice, I changed the program code. But now its showing wrong
answer.
My new code is:
import java.io.*;
class Solution
{
public static void main(String args[])throws IOException
{
InputStreamReader read =new InputStreamReader(System.in);
BufferedReader in =new BufferedReader(read);
int a,b,n,i,j,t=0,c=0,pos=0;
a=Integer.parseInt(in.readLine());
int sol[] =new int[a];
for(b=1;b<=a;b++)
{
n=Integer.parseInt(in.readLine());
int ar[] =new int[n];
String s =in.readLine();
String[] strs = s.trim().split("\\s+");
for(i=0;i<strs.length;i++)
{
ar[i]=Integer.parseInt(strs[i]);
}
for(i=0;i<n-2;i++)
{
for(j=0;j<n-i-2;j++)
{
if(ar[j]>ar[j+2])
{
t=ar[j];
ar[j]=ar[j+2];
ar[j+2]=t;
}
}
}
for(i=0;i<n-1;i++)
{
for(j=0;j<n-i-1;j++)
{
if(ar[j]>ar[j+1])
{
pos=j;
c++;
}
}
}
if(c==0)
{
sol[b-1]=0;
}
else
{
sol[b-1]=pos;
}
}
for(b=0;b<a;b++)
{
if(sol[b]==0)
{
System.out.println("Case #"+(b+1)+": OK");
}
else
{
System.out.println("Case #"+(b+1)+": "+sol[b]);
}
}
}
}
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