I have tested many different scenarios and test cases , And my code has
successfully produced outputs-As the problem suggests there can be many
solution I need to show any one but don't know why is it failing?
def FourPresent(n):
f=0
#print("for ",n)
while(n>0):
a=n%10
#print("now checking digit ",a)
if a==4:
f=1
break
n=n//10
if f==0:
return False
else:
return True
def chk_Four_occurance_lowest_place(n):
nd=1
while n>0:
if n%10==4:
return nd
nd+=1
n=n//10
return nd
def no_of_dig(n):
c=0
while(n>0):
c+=1
n=n//10
return c
t=int(input())
for ix in range(t):
n=int(input())
nod=no_of_dig(n)
if nod==1:
a=n//2
b=n-a
else:
nd=nod-2
#c=5*(10**nd)+1
a=n
b=n-a
while(FourPresent(a) or FourPresent(b)):
pd=chk_Four_occurance_lowest_place(a)
if pd<=2:
p=pd-1
else:
p=pd-2
inc_fact=5*(10**p)+1
a-=inc_fact
b=n-a
#print("now pd ",pd,inc_fact)
#print("After operation a,b",a,b)
print("Case #{}: {} {}".format(ix+1, a, b))
Thanks in advance for your help!!
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