Hello,
I got a MLE on the problem You Can Go Your Own Way with the following code:
```cpp
#include <cstring>
#include <iostream>
#include <stdio.h>
#include <string>
using namespace std;
int cases, N;
char buffer[50005], ans[50005];
int main(int argc, const char **argv) {
scanf("%d", &cases);
for(int case_i = 1; case_i <= cases; ++case_i) {
scanf("%d%s", &N, buffer);
int s = strlen(buffer);
for(int i = 0; i < s; ++i) {
if (buffer[i] == 'E') {
ans[i] = 'S';
} else {
ans[i] = 'E';
}
}
ans[s] = '\0';
printf("Case #%d: %s\n", case_i, ans);
}
return 0;
}
```
I tried to figure out what was the problem and I discover that when I declare
the variables like the following, I get a correct status:
```
char buffer[50005], ans[50005];
int cases, N;
```
So, my questions are:
* is it a normal behavior or did I miss something
* how can I check the over memory limit locally, I tested with /usr/bin/time
-v but nothing special was raised
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