[Contacts API] “Next” parameter is bad or missing

Sun, 08 Jan 2012 08:46:36 -0800 

<!doctype html>

<HTML>
<HEAD>

<script type="text/javascript" src="http://www.google.com/jsapi";></
script>
<script type="text/javascript" src="http://gdata-javascript-
client.googlecode.com/svn/trunk/samples/contacts/contacts_picker/
picker.js"></script>
<script>

google.load("gdata", "1.x");
var contactsService;

google.setOnLoadCallback(initFunc);
var scope;
var token;



function setupContactsService() {
  contactsService = new
google.gdata.contacts.ContactsService('exampleCo-exampleApp-1.0');
}

function logMeIn() {
  scope = 'https://www.google.com/m8/feeds/contacts/default/full';
  if (location.hash == ""){
    token = google.accounts.user.login(scope);
  }
}

function initFunc() {
  setupContactsService();

  logMeIn();

  getMyContacts()
}

function doCheck(){
  scope = "http://www.google.com/calendar/feeds";;
  token = google.accounts.user.checkLogin(scope);
}

function getMyContacts() {
  var contactsFeedUri = 'https://www.google.com/m8/feeds/contacts/
default/full';
  var query = new google.gdata.contacts.ContactQuery(contactsFeedUri);

  // Set the maximum of the result set to be 5
  query.setMaxResults(3000);

  contactsService.getContactFeed(query, handleContactsFeed,
handleError);
}

var handleContactsFeed = function(result) {
  var entries = result.feed.entry;
  var totalsSet=0;
  var allAddress = "";

  for (var i = 0; i < entries.length; i++) {
    var contactEntry = entries[i];
    var emailAddresses = contactEntry.getEmailAddresses();

    if (emailAddresses[0])
    {
      emailAddress = emailAddresses[0].getAddress();
      newName = contactEntry.getTitle().getText();

      allAddress += emailAddress+"|sepa|"+newName+",";
      totalsSet++;
    }

  }
  if (totalsSet>0)
  {

    try
    {
      //window.opener.fillBg();
    }
    catch(err)
    {
      alert(err.description)
      alert(err.line)
    }
    window.opener.$("contactsSearch").innerHTML = "<img src='../../
images/ajax_blue.gif' border=0 hspace=0 vspace=0 />";
    window.opener.moreInfoPAsy("welcome/friends-find-
Viewer.asp","emails="+allAddress.replace(/,/
g,String.fromCharCode(1)),window.opener.contactsSearchDiv,alert);

    window.close();
    google.accounts.user.logout()
  }
}
function handleError(e) {
  //alert("There was an error!");
  //alert(e.cause ? e.cause.statusText : e.message);
}

</script>
</HEAD>
<BODY>
<img src="../../../images/logo.gif" style="position:absolute; top:
-1000px;" />
</BODY>
</HTML>


------------------------------


That's my code. When I'm running it on http protocol it works great,
but when i use the https protocol (that's how my site works) - i get
the error message.

"The page you have requested cannot be displayed. Another site was
requesting access to your Google Account, but sent a malformed
request. Please contact the site that you were trying to use when you
received this message to inform them of the error. A detailed error
message follows:

The "next" parameter was bad or missing."

any help?

thanks.

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