Finally decyphered the google documentation. A DocId is a "docId" and not a filename. When I first read it, it was a logical assumption that the DocId would be the name of the file. It would seem more logical to me that a with a feed, you would specify what you know, which is the filename, rather than having to do the extra step of looking-up/converting from a filename to a document id.
Neal print "-----------------Get Matching Filename/DocId -------------" q = gdata.docs.service.DocumentQuery() q['title'] = '3WCTest' q['title-exact'] = 'true' feed = client.Query(q.ToUri()) PrintFeed(feed) docId = feed.entry[0].resourceId.text domain = "docs.google.com" print "-----------------Get Doc Contents ---------------" url = "http://"; + domain + "/feeds/download/documents/Export?docID=" + docId + "&exportFormat=" + exportFormat print "url = " + str(url) result = client.Get(url,converter=str) print "---- Results: ------- " print "Google GDocs Response 2: " + result --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Google Docs Data APIs" group. To post to this group, send email to Google-Docs-Data-APIs@googlegroups.com To unsubscribe from this group, send email to google-docs-data-apis+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/Google-Docs-Data-APIs?hl=en -~----------~----~----~----~------~----~------~--~---
