thor. many thanks, that script is just what i was looking for.  since
it didn't need it to be very fine I was also able to figure out the
feet per second in seattle and feet per second (of long) in florida
and use those rough numbers, but your link if much more refined.

Sam


On Sep 25, 10:32 pm, Thor <[EMAIL PROTECTED]> wrote:
> Check out the destPoint function 
> at:http://www.movable-type.co.uk/scripts/latlong.html
>
> On Sep 26, 12:17 pm, This Guy <[EMAIL PROTECTED]> wrote:
>
>
>
> > I guess if we are dealing with distances of 10 miles might that curve
> > be negligible, right? I only need accuracy within a mile so i could
> > probably just add and subtract the appropriate minutes...
>
> >   I am curious as to the answer to the below problem.
>
> > On Sep 25, 10:11 pm, This Guy <[EMAIL PROTECTED]> wrote:
>
> > > I think this is a great circle calculation, one that googlemaps can
> > > do.  However, in order to sort a large dataset in sql for display I
> > > need to be able to find four points (n, e, s, w) that are 10 miles
> > > away from my center point and then find the lat and long for each of
> > > those points.
>
> > > that way I can use the lat and long to sort the large dataset before
> > > doing a radii search...
>
> > > someone else is doing most of the programing, but I think this is a
> > > great circle calculation...would I need to put the formula below in on
> > > some other side or is there a googlemap way to do this.
>
> > > Dollar to anyone who can help me.
>
> > > A point {lat,lon} is a distance d out on the tc radial from point 1
> > > if:
>
> > >      lat=asin(sin(lat1)*cos(d)+cos(lat1)*sin(d)*cos(tc))
> > >      IF (cos(lat)=0)
> > >         lon=lon1      // endpoint a pole
> > >      ELSE
> > >         lon=mod(lon1-asin(sin(tc)*sin(d)/cos(lat))+pi,2*pi)-pi
> > >      ENDIF- Hide quoted text -
>
> - Show quoted text -
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