[EMAIL PROTECTED] wrote:
> On Oct 13, 8:33 am, ramasaig <[EMAIL PROTECTED]> wrote:
>> On Oct 13, 4:08 pm, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]>
>> wrote:
>>
>>
>>
>>> On Oct 13, 7:46 am, Mike Williams <[EMAIL PROTECTED]> wrote:
>>>> You could write something like this
>>>> GEvent.addListener(map, 'click', function(overlay, latlng) {
>>>> if (overlay) {
>>>> if (overlay instanceof GPolygon) {
>>>> if (overlay.isHidden()) {
>>>> overlay.show();
>>>> } else {
>>>> overlay.hide();
>>>> }
>>>> }
>>>> }
>>>> });
>>> Does clicking on a hidden overlay work?
>>> I would have thought that would work for hiding the overlays, but not
>>> for showing them again.
>>> -- Larry
>> You are right, it does hide the overlays, but won't show them again.
>> The click is detected, but 'if (overlay)' is now false (because it's
>> hidden, I assume ?).
>>
>> This is only my second day on Google maps (though I've used JS
>> before), and I'm confused because I understood GPolygon had been made
>> clickable recently (v. 2.88). I had therefore expected something like:
>>
>> GEvent.addListener(polygon, 'click', function(arguments) {....
>> would work, but clearly not.
>>
>> You say I must _use_ the arguments. OK, but I'm not sure how, other
>> than in the function. I'll add 'overlaylatlng' as well
>> I'll try Mike Williams' script too.
>
> Try this (make your map variable and your polygon variables global):
> GEvent.addListener(map, 'click', function(overlay, latlng,
> overlaylatlng) {
> // GLog.write("map click ("+overlay+","+latlng+","+overlaylatlng+")");
> if (overlay) {
> if (overlay instanceof GPolygon) {
> if (overlay.isHidden()) {
> overlay.show();
> } else {
> overlay.hide();
> }
> }
> } else if (latlng) {
> if (polyNW.Contains(latlng)) {polyNW.show();}
> if (polyCT.Contains(latlng)) {polyCT.show();}
> if (polySE.Contains(latlng)) {polySE.show();}
> if (polySW.Contains(latlng)) {polySW.show();}
> }
> });
>
> The overlaylatlng argument is undefined sometimes, I don't understand
> why. I though it was supposed to _always_ return a valid value.
>
> -- Larry
Thanks. I'll try that and let you know what happens.
Tim
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