You can use these objects to parse XML:
GDownloadUrl("files.xml", function(data, responseCode) {
if(responseCode == 200) {
var xml = GXml.parse(data);
var markers = xml.documentElement.getElementsByTagName("user");
or PHP Xpath - works very well!
On Oct 15, 7:48 am, Terk <[EMAIL PROTECTED]> wrote:
> Tubby
>
> The link has a lot of info.
> The database that i've use was Access 2007, (after reading Pamelas
> Foxhttp://code.google.com/support/bin/answer.py?answer=65622&topic=11369
> will change to MySQL )
> So the question comes down to this,
> Is their a function that will extract only the information from the
> XMl file requested by the user?
> something like GXml.
>
> The process so far looks like Pamela Fox, (Database, population,
> output to xml or create xml)
>
> I my logic wrong or the structure ?
>
> Thank you Tubby
>
> On Oct 15, 12:29 am, Tubby Grey <[EMAIL PROTECTED]> wrote:
>
>
>
> > Maybe this link will work:
>
> >http://tinyurl.com/3k4z8x
>
> > On Oct 14, 8:12 pm, Mike Williams <[EMAIL PROTECTED]> wrote:
>
> > > The only sensible way to deal with that amount of data is to use a
> > > database. See:
>
> > >http://groups.google.com/group/Google-Maps-API/web/using-databases-wi...
> > > maps-apps
>
> > > --http://econym.org.uk/gmap
> > > The Blackpool Community Church Javascript Team- Hide quoted text -
>
> - Show quoted text -
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