Thanks Neil!
On Mar 11, 4:21 pm, "neil.young" <[email protected]> wrote:
> See below. Use:
>
> TileCoordinate c = new TileCoordinate(lat, lon, zoom);
> if (c.locationCoord()) {
> // Do whatever
>
> }
>
> whereas lat, lon is the geocoordinate (e.g. 52.123, 13.123) and zoom is
> the Google zoom stage (0...17). The resulting x,y is the image
> coordinate within the big, fat picture, Google draws for us. The int
> part may be used directly to obtain the tiles (Attention: Illegal) using
> a URL formed like this:
>
> String.Format("http://mt.google.com/mt?x={0}&y={1}&zoom={2}";, c.x, c.y,
> 17-zoom)
>
> The fractional part times 256 is the pixel coordinate within the tile
> itself.
>
> Regards
>
> using System;
> using System.Collections.Generic;
> using System.Text;
>
> namespace TileRequest {
> class TileCoordinate {
> public TileCoordinate(double lat, double lon, int zoom) {
> this.lat = lat;
> this.lon = lon;
> this.zoom = zoom;
> }
> public double y;
> public double x;
>
> public double lat;
> public double lon;
> public int zoom;
>
> public bool locationCoord() {
> if (System.Math.Abs(this.lat) > 85.0511287798066)
> return false;
> double sin_phi = System.Math.Sin(this.lat * System.Math.PI /
> 180);
> double norm_x = this.lon / 180;
> double norm_y = (0.5 * System.Math.Log((1 + sin_phi) / (1 -
> sin_phi))) / System.Math.PI;
> this.y = System.Math.Pow(2, this.zoom) * ((1 - norm_y) / 2);
> this.x = System.Math.Pow(2, this.zoom) * ((norm_x + 1) / 2);
> return true;
> }
> }
>
>
>
> }- Hide quoted text -
>
> - Show quoted text -
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